Question

我无法正确说出来，也无法在文档中找到它，但我如何添加到中间版＆＃39;通过＆＃39;向其添加新对象时ManyToManyField的模型？

请注意，它是一种递归关系，但我使用ManyToMany，因为我不确定OneToOne是否支持＆＃34;通过＆＃34; model（文档没有指定）

~~无论Person_Person字段如何，都将使用curr_partner，向其中添加父/子关系等对象（Person中没有字段）~~ （这是因为ManyToManyField是SQL关系数据库中输出表中的实际字段的混淆）

（我意识到我的模型存在一些上下文/理论上的缺陷，但现在让我们抽象出来）

例如

Models.py：

class Person(models.Model):
    objectid = models.AutoField(primary_key=True)
    name = models.CharField()
    curr_partner = models.ManyToManyField(
        self, 
        on_delete = models.CASCADE, 
        through = Person_Person, #This lets you define the model that will act as an intermadiary
        symmetrical = False, #This needs to be set with recursive relationships
    )

class Person_Person(models.Model):
    person_1 = models.ForeignKey(Person, ondelete=models.CASCADE)
    person_2 = models.ForeignKey(Person, ondelete=models.CASCADE)
    relation = models.ChoiceField(            
        ('P', 'Parent'),
        ('C', 'Child'),
        ('E', 'Engaged'),
        ('W', 'Widow'),
    )

查询：

#Adding a married couple

father = Person(name = "John")
mother = Person(name = "Anna")

father.curr_partner.add( mother , through.relation = "Engaged") #???

#Adding a 'Child' relation

child = Person(name = "Billy")

#This makes sense??
p1 = Person_Person(person1 = father, person2 = child, relation = "Child")
p2 = Person_Person(person1 = mother, person2 = child, relation = "Child")

Answer 1

您可以通过保存关系模型的实例来创建关系，就像您（几乎）对孩子一样。你有像

这样的东西

public class AddressModel : IValidatableObject
{
    [Required]
    public string Country { get; set; }
    public string State { get; set; }

    public IEnumerable<ValidationResult> Validate(ValidationContext validationContext)
    {
        if(Country == "United States" && String.IsNullOrEmpty(State))
        {
            yield return new ValidationResult("State is required for United States", new [] { nameof(State) });
        }
    }
}

顺便说一句，您的

father = Person(name = "John")
mother = Person(name = "Anna")

marriage = Person_Person.objects.create(person1=father, person2=mother, relation="E")

p1 = Person_Person.objects.create(person1=father, person2=child, relation="C")
p2 = Person_Person.objects.create(person1 = mother, person2 = child, relation="C")

属性没有准确的名称，因为它实际上表示了所有人的关系，而不仅仅是婚姻。也许您应该将其重命名为curr_partner或relationships并拥有一个属性来获取此人的合作伙伴：

kindred

Django如何填充＆＃39; trough＆＃39;将对象添加到ManyToManyField时的中间模型？

1 个答案: