我有这5个sale_order
直接连接到sale_order_line
的表,其中包含与product_product
连接的product_template
连接到mrp_bom
的订单产品其中一个名为bom_line
的表可以连接到产品模板,另一个表连接到836g
。我正在尝试输出包含单词Select so.name,
pt.name,
sol.name
From sale_order so
Inner Join sale_order_line sol
On so.id = sol.order_id
Inner Join product_template pt
On sol.product_id = pt.id
Inner Join mrp_bom bom
On pt.id = bom.product_tmpl_id
Inner Join mrp_bom_line boml
On bom.id = boml.bom_id
Where boml.product_id = (Select id From product_template Where name Like '%836g%'
Order By so.name
这是我到目前为止所做的:
836g
此代码输出错误,因为我有=
的3个项目。我尝试将条件中的IN
更改为id
,以便它会抓取它将返回的所有pub trait DiGraph<'a> {
type N;
fn nodes<T>(&'a self) -> T where T: Iterator<Item=&'a Self::N>;
fn pre<T>(&'a self, node: Self::N) -> T where T: Iterator<Item=&'a Self::N>;
fn succ<T>(&'a self, node: Self::N) -> T where T: Iterator<Item=&'a Self::N>;
}
struct SimpleNode {
pre: Vec<usize>,
succ: Vec<usize>,
}
pub struct SimpleDiGraph {
pub nodes: Vec<SimpleNode>
}
impl<'a> DiGraph<'a> for SimpleDiGraph {
type N = usize;
fn nodes<T=std::ops::Range<usize>>(&'a self) -> T {
return std::ops::Range { start: 0, end: self.nodes.len() };
}
fn pre<T=std::slice::Iter<'a,usize>>(&'a self, node: usize) -> T {
return self.nodes[node].pre.iter();
}
fn succ<T=std::slice::Iter<'a,usize>>(&'a self, node: usize) -> T {
return self.nodes[node].succ.iter();
}
}
。但它仍然给我一个错误。这是我迄今为止最好的,我已经尝试了很多次,但我无法弄清楚。
答案 0 :(得分:0)
我觉得这些内容是你真正想要的东西:
f(c("a","b","d"), df)
#[1] 0.6
f(c("a","d"), df)
#[1] 1
答案 1 :(得分:0)
OMG!我刚才得到了答案。我不认为这会对任何人有所帮助,但我会发布我的答案
SELECT so.name,
pt.name PT,
sol.name SOL,
(Select pp1.name_template From product_product pp1 Where boml.product_id = pp1.id) BOML,
boml.product_id
FROM sale_order so INNER JOIN sale_order_line sol ON so.id = sol.order_id INNER JOIN product_template pt ON sol.product_id = pt.id INNER JOIN mrp_bom bom ON pt.id = bom.product_tmpl_id INNER JOIN mrp_bom_line boml ON bom.id = boml.bom_id WHERE(选择pp1.name_template来自product_product pp1,其中boml.product_id = pp1.id)LIKE&#39;%836g%&#39; ORDER BY so.name
谢谢大家帮助我的努力!我们来到这里的社区很棒! :d