Question

因此，如果LARGE不等于Count，那么LARGE应该增加，直到Count和LARGE具有相同的值。事情发生之后，我的教授想再次输入一个新的整数，然后它会再次循环，但我不知道如何让我的代码回到while。

if (LARGE == Count)
{
    System.out.println ("Large is Equal to Count");
}

while (Count != LARGE)
{
    LARGE++;
    System.out.println ("Large is " +LARGE);
}

if (LARGE == Count)
{
    System.out.println ("Input a new integer to compare")
    LARGE = input.newInt();
}

Answer 1

根据我的理解，这就是你想要的。

public static void main(String[] args) {

        int LARGE = 0;
        int Count = 0;
        String s = null;
        Scanner sc = new Scanner(System.in);
        do {

            LARGE = sc.nextInt();
            Count = sc.nextInt();

            if (LARGE == Count) {
                System.out.println("Large is Equal to Count");
            } else {
                do {
                    LARGE++;
                    System.out.println("Large is " + LARGE);
                } while (Count != LARGE);

                if (LARGE == Count) {
                    System.out.println("Large is Equal to Count");
                    System.out.println("Input a new integer to compare");
                }

            }

            System.out.println("Do you want to continue? If yes then Press Y");
            s = sc.next();
        } while (s.equalsIgnoreCase("Y"));

    }

Answer 2

教授想要永远输入新整数的次数是多少？我假设它1000次。如果永远，将'times'替换为true，而其他大括号则为'times'而不是1000分配一些有意义的东西。

System.out.println ("Input a new integer to compare")
LARGE = input.newInt();
int times = 1000; // number of times prof want to enter new integer.
int loop = 0;
while(times > loop ){
    while (Count != LARGE)
    {
        LARGE++;
        System.out.println ("Large is " +LARGE);
    }
    System.out.println ("Input a new integer to compare")
    LARGE = input.newInt();
    loop++;
}

Java如何跳回While循环

2 个答案: