Question

我读了这个xml并尝试获取不同的节点值。我可以只查找特定节点并获取值，但问题是有多个节点具有相同的名称。所以，当我得到它的值时，它给了我指定的所有节点值。我想分别获取每个节点的值。任何帮助将不胜感激。提前谢谢。

这是xml：

 <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register1</Operation>
  </LogLine>
  <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register2</Operation>
  </LogLine>
  <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register3</Operation>
  </LogLine>

我做了什么

success: function(xml) {
var xmlDoc = jQuery.parseXML(xml);          
xmlDoc = $.parseXML( xml ),
$xml = $( xmlDoc ),
$dateTime = $xml.find( "DateTime" );
$( "#xmlElement" ).append( "Log In Information:    "+$dateTime .text() );
}

HTML：

当前输出： 2016-11-17T18：31 + 00002016-11-17T18：31 + 00002016-11-17T18：31 + 0000

Answer 1

这似乎有效，

您的XML最初无效，我添加了LINES，部分..

var xml = `<Lines>
  <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register1</Operation>
  </LogLine>
  <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register2</Operation>
  </LogLine>
  <LogLine>
     <DateTime>2016-11-17T16:48+0000</DateTime>
     <Operation>Register3</Operation>
  </LogLine></Lines>`;

$(function () {
  var xmlDoc = $($.parseXML( xml ));
  xmlDoc.find('Lines LogLine').each(function () {
    var $t = $(this);
    console.log(
      $t.find('DateTime').text() + '  ' +
      $t.find('Operation').text()  
    );
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

试试这个，

 success: function(xml) {
    var resultXML = $.parseXML(xml);
    //loop over each 'LogLine' element node
    $(resultXML).find('LogLine').each(function(index){
       //within each 'LogLine' node find 'DateTime' node
       var dateTime = $(this).find( "DateTime" );
       $( "#xmlElement" ).append( "Log In Information:    "+dateTime.text() );
    }
 }

Jquery检索对象值

2 个答案: