如何从对象中获取价值?

时间:2018-10-12 10:06:57

标签: jquery json

如何才能仅捕获此对象中image之后的值?我只想要:/images/aluguer/7d9a3d3c-08bd-44a8-a081-b6a764cc7ef4.jpg

{
  "data": {
    "file": {
      "tmp_name": "/private/var/tmp/phpQhqg0D",
      "error": 0,
      "name": "ferrari3.jpg",
      "type": "image/jpeg",
      "size": 336044
    },
    "image": "/images/aluguer/7d9a3d3c-08bd-44a8-a081-b6a764cc7ef4.jpg"
  }
}

0 个答案:

没有答案