如何从JSON响应中获取值

时间:2016-11-18 06:07:58

标签: c# json

我必须来自数据库API的JSON响应。

我的JSON数据:

{
    "AccessToken":"1929c63a-9c72-4c0d-aea8-345c0b5411e9",
    "LoggedInUserID":1,
    "LookupData":{
        "LiquiditySources":[
            {
                "ID":1,
                "ParentID":null,
                "Name":"testname1",
                "SequenceNo":null,
                "Caption":"test1",
                "ConnectivityInfo":
                    "{\"Port\":11111,\"Username\":testuser1,\"Password\":\"password1\"}"
            },
            {
                "ID":2,
                "ParentID":null,
                "Name":"testname2",
                "SequenceNo":null,
                "Caption":"test2",
                "ConnectivityInfo":
                    "{\"Port\":22222,\"Username\":testuser2,\"Password\":\"password2\"}"
            }
        ]
    }
}

我想将这个响应值存储在不同的变量中,请任何人帮助我这是我的最后一年项目。我正在使用Windows应用程序c#

1 个答案:

答案 0 :(得分:1)

您应该将此JSON反序列化为类,然后使用类对象执行任何操作。

您可以使用NewtonSoft.Json dll来实现此目的。

public class LiquiditySource
{
    public int ID { get; set; }
    public object ParentID { get; set; }
    public string Name { get; set; }
    public object SequenceNo { get; set; }
    public string Caption { get; set; }
    public string ConnectivityInfo { get; set; }
}

public class LookupData
{
    public List<LiquiditySource> LiquiditySources { get; set; }
}

public class SampleClass
{
    public string AccessToken { get; set; }
    public int LoggedInUserID { get; set; }
    public LookupData LookupData { get; set; }
}

string json = "your json string";
SampleClass obj = JsonConvert.DeserializeObject<SampleClass>(json);

您可以获得以下属性:

List<LiquiditySource> ls =  obj.LookupData.LiquiditySources;
    foreach(LiquiditySource liquiditySource in ls)
    {
        string connectivityInfo = liquiditySource.ConnectivityInfo;

    }

如果您只想获取所有ConnectivityInfo值,也可以使用LINQ

List<string> lsConnectivityInfo = obj.LookupData.LiquiditySources.Select(c => c.ConnectivityInfo).ToList();

如果你想将connectivityInfo字符串deserilize到object并获取它的属性,那么你必须再次将它反序列化为object。 注意:您还必须修改JSON。

修改JSON:

{
    "AccessToken": "1929c63a-9c72-4c0d-aea8-345c0b5411e9",
    "LoggedInUserID": 1,
    "LookupData": {
        "LiquiditySources": [{
            "ID": 1,
            "ParentID": null,
            "Name": "testname1",
            "SequenceNo": null,
            "Caption": "test1",
            "ConnectivityInfo": "{\"Port\":11111,\"Username\":\"testuser1\",\"Password\":\"password1\"}"
        }, {
            "ID": 2,
            "ParentID": null,
            "Name": "testname2",
            "SequenceNo": null,
            "Caption": "test2",
            "ConnectivityInfo": "{\"Port\":22222,\"Username\":\"testuser2\",\"Password\":\"password2\"}"
        }]
    }
}

再上一堂课:

public class ConnectivityInfo
{
    public int Port { get; set; }
    public string Username { get; set; }
    public string Password { get; set; }
}

然后这样做:

foreach (LiquiditySource liquiditySource in ls)
    {
        string connectivityInfo = liquiditySource.ConnectivityInfo;
        ConnectivityInfo connectivityInfoObj = JsonConvert.DeserializeObject<ConnectivityInfo>(connectivityInfo);

    }
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