Question

我正在尝试从下面提到的values (ID as a string, branches of address_one and two)响应中获取特定JSON。请帮我。

我的回复

{ 
   "response":{ 
      "school":"inox",
      "grad":"first",
     },
   "ID":"1234567890101112",
   "branches":{ 
      "address_one":"ISA",
      "address_two":"DOA"
   },
   "my school":{ 
      "inox":"first"
   },
}

我的代码：

try {
        JSONObject data = response.getJSONObject("response");
        String school_value = data.getString(KEY_SCHOOL);
        String grad_value = data.getString(KEY_GRAD);

       System.out.println("RESPONSE:" + data + school_value + grad_value);

     } catch (JSONException e) {
                    e.printStackTrace();
                    Toast.makeText(getApplicationContext(),
                            "Error: " + e.getMessage(),
                            Toast.LENGTH_LONG).show();
     }

Answer 1

ID位于response JSONObject中。 address_one内的address_two和branches个JSONObject位于response JSONObject内部：

// get ID
String strID= response.optString("ID");

// get branches JSONObject 
JSONObject jsonBranches = response.getJSONObject("branches");

// get address_one and address_two from jsonBranches

//address_one
String address_one= jsonBranches.optString("address_one");

//address_two
String address_two= jsonBranches.optString("address_two");

Answer 2

如果你的字符串中的响应然后首先在json对象中转换它，然后在解析之后如果没有得到则在检查你的参数与json key匹配后

 JSONObject response =new JSONObject(response_string);
  JSONObject data = response.getJSONObject("response");
  String school_value = data.getString("school");
  String grad_value = data.getString("grad");

Answer 3

首先，您发布的代码段不是有效的json。我认为，正确的形式是在关闭大括号之前没有逗号：

{
  "response": {
    "school": "inox",
    "grad": "first"
  },
  "ID": "1234567890101112",
  "branches": {
    "address_one": "ISA",
    "address_two": "DOA"
  },
  "my school": {
    "inox": "first"
  }
}

除此之外，您的代码似乎没问题。要获取地址，首先获取分支对象，然后获取地址字符串：

JSONObject branches = response.getJSONObject("branches");
String address1 = branches.getString("address_one");
String address2 = branches.getString("address_two");

希望它能奏效。

Answer 4

像这样使用。

.previewing{

    padding-bottom:10px;
    padding-top:0px;
    margin-bottom:0px;
    border-width: 0px;
    border-style:none;
    transition: all .2s ease-in-out;
    -webkit-animation: fadein 2s;
    -moz-animation: fadein 2s; 
    -ms-animation: fadein 2s;
    -o-animation: fadein 2s; 
    animation: fadein 2s;

}

@keyframes fadein {
    from { opacity: 0; }
    to   { opacity: 1; }
}

@-moz-keyframes fadein {
    from { opacity: 0; }
    to   { opacity: 1; }
}

@-webkit-keyframes fadein {
    from { opacity: 0; }
    to   { opacity: 1; }
}

@-ms-keyframes fadein {
    from { opacity: 0; }
    to   { opacity: 1; }
}

@-o-keyframes fadein {
    from { opacity: 0; }
    to   { opacity: 1; }
}


.previewing:hover{ 
    transform: scale(1.02);
}

Answer 5

通过这种方式你可以访问所有的值....`try { JSONObject responceData = response.getJSONObject（“response”）; String school_value = responceData.getString（KEY_SCHOOL）; String grad_value = responceData.getString（KEY_GRAD）;

    String id = response.getString("1234567890101112")

    JSONObject brances = response.getJSONObject("branches");
    String address_one = brances.getString("address_one");
    String address_two = brances.getString("address_one");

    JSONObject myScool = response.getJSONObject("my school");
    String inox = brances.getString("inox");

    System.out.println("Responce in Json: " + responce.toString);
    System.out.println("Responce extracted: " + school_value + " " + grad_value + 
            " " + id + " " +address_one + " " + address_two + " " + inox);


} catch (JSONException e) {
    e.printStackTrace();
    Toast.makeText(getApplicationContext(),
            "Error: " + e.getMessage(),
            Toast.LENGTH_LONG).show();
}`

Answer 6

将其替换为您的代码，您将在SOP中打印ID

 try {
            JSONObject data = response.getJSONObject("response");
            String school_value = data.getString(KEY_SCHOOL);
            String grad_value = data.getString(KEY_GRAD);
             String id=response.getString("ID");

    System.out.println("RESPONSE:" + data + school_value + grad_value+id);

     } catch (JSONException e) {
                    e.printStackTrace();
                    Toast.makeText(getApplicationContext(),
                            "Error: " + e.getMessage(),
                            Toast.LENGTH_LONG).show();
     }

如何从JSON响应Android中获取特定值？

6 个答案: