Question

我尝试了以下代码。

var SeatWithCat = [{
  "level": "Level II",
  "price": 5,
  "quantity": 1,
  "seats": "B3"
}, {
  "level": "Level II",
  "price": 5,
  "quantity": 1,
  "seats": "B1"
}, {
  "level": "Level I",
  "price": 10,
  "quantity": 1,
  "seats": "A2"
}, {
  "level": "Level III",
  "price": 30,
  "quantity": 1,
  "seats": "C1"
}, {
  "level": "Level III",
  "price": 30,
  "quantity": 1,
  "seats": "C2"
}, {
  "level": "Level V",
  "price": 50,
  "quantity": 1,
  "seats": "E1"
}, {
  "level": "Level II",
  "price": 5,
  "quantity": 1,
  "seats": "B2"
}, {
  "level": "Level VI",
  "price": 2,
  "quantity": 1,
  "seats": "F1"
}];
var temp = [];
var jsonarr = [];
for (var i = 0; i < SeatWithCat.length; i++) {
  for (var j = 1; j < SeatWithCat.length; j++) {
    if (SeatWithCat[i].level === SeatWithCat[j].level) {
      temp.push({
        level: SeatWithCat[i].level,
        quantity: SeatWithCat[i].quantity + SeatWithCat[j].quantity,
        price: SeatWithCat[i].price + SeatWithCat[j].price,
        seats: SeatWithCat[i].seats + "," + SeatWithCat[j].seats
      });
      SeatWithCat = SeatWithCat.filter(function(el) {
        return el.level !== SeatWithCat[i].level;
      });
      jsonarr = SeatWithCat;
      alert(JSON.stringify(temp));
    }
  }
}
var finalObj = temp.concat(jsonarr);
alert(JSON.stringify(finalObj));

输出：

[{
  "level": "Level II",
  "quantity": 2,
  "price": 10,
  "seats": "B3,B1"
}, {
  "level": "Level III",
  "quantity": 2,
  "price": 60,
  "seats": "C1,C1"
}, {
  "level": "Level VI",
  "quantity": 2,
  "price": 4,
  "seats": "F1,F1"
}, {
  "level": "Level I",
  "price": 10,
  "quantity": 1,
  "seats": "A2"
}, {
  "level": "Level V",
  "price": 50,
  "quantity": 1,
  "seats": "E1"
}]

它对于具有相同级别的两个对象工作正常但如果阵列中有多于两个对象且具有相同级别则不起作用。我的要求是为具有相同级别的任意数量的对象添加值。提前谢谢！

Answer 1

您可以使用Array.prototype.reduce()收集字典中的唯一项目，然后使用Array.prototype.map()将字典转换回数组：

＆＃13;

function combine(arr) {
  var combined = arr.reduce(function(result, item) {
    var current = result[item.level];

    result[item.level] = !current ? item : {
      level: item.level,
      price: current.price + item.price,
      quantity: current.quantity + item.quantity,
      seats: current.seats + ',' + item.seats
    };

    return result;
  }, {});

  return Object.keys(combined).map(function(key) {
    return combined[key];
  });
}

var SeatWithCat = [{"level":"Level II","price":5,"quantity":1,"seats":"B3"},{"level":"Level II","price":5,"quantity":1,"seats":"B1"},{"level":"Level I","price":10,"quantity":1,"seats":"A2"},{"level":"Level III","price":30,"quantity":1,"seats":"C1"},{"level":"Level III","price":30,"quantity":1,"seats":"C2"},{"level":"Level V","price":50,"quantity":1,"seats":"E1"},{"level":"Level II","price":5,"quantity":1,"seats":"B2"},{"level":"Level VI","price":2,"quantity":1,"seats":"F1"}];

var result = combine(SeatWithCat);

console.log(result);

＆＃13;

Answer 2

您可以使用哈希表作为对结果集中相同级别对象的引用。

迭代数组并检查哈希 - 如果没有设置，则生成具有实际属性的新对象。否则，请添加quantity并附加seats。

此提案仅使用一个循环。

var seatWithCat = [{ level: "Level II", price: 5, quantity: 1, seats: "B3" }, { level: "Level II", price: 5, quantity: 1, seats: "B1" }, { level: "Level I", price: 10, quantity: 1, seats: "A2" }, { level: "Level III", price: 30, quantity: 1, seats: "C1" }, { level: "Level III", price: 30, quantity: 1, seats: "C2" }, { level: "Level V", price: 50, quantity: 1, seats: "E1" }, { level: "Level II", price: 5, quantity: 1, seats: "B2" }, { level: "Level VI", price: 2, quantity: 1, seats: "F1" }],
    result = [];

seatWithCat.forEach(function (o) {
    if (!this[o.level]) {
        this[o.level] = { level: o.level, price: o.price, quantity: o.quantity, seats: o.seats };
        result.push(this[o.level]);
        return;
    }
    this[o.level].quantity += o.quantity;
    this[o.level].seats += ',' + o.seats;
}, Object.create(null));

console.log(result);

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Answer 3

我强烈推荐使用lodash和他们精美的瑞士军刀工具，而不是自己编写。你可能需要更多。 https://lodash.com/docs/4.16.4

如何将JSON对象与相同的键组合并添加其他相应的值？

3 个答案: