标题几乎说明了一切。如果日期与具有相同项目ID的特定数组中的其他日期匹配，我正在尝试组合数组。所以例如有。这是我到目前为止所做的。
Array
(
[1488] => Array
(
[project_name] => test
[hours] => Array
(
[0] => Array
(
[0] => 2016-07-11 - 2016-07-17
[1] => 37
)
[1] => Array
(
[0] => 2016-07-04 - 2016-07-10
[1] => 51
)
[2] => Array
(
[0] => 2016-07-04 - 2016-07-10
[1] => 44
)
[3] => Array
(
[0] => 2016-07-04 - 2016-07-10
[1] => 22
)
)
)
[2] => Array
(
[project_name] => Invoice 78554
[hours] => Array
(
[0] => Array
(
[0] => 2016-06-13 - 2016-06-19
[1] => 10
)
)
)
[3] => Array
(
[project_name] => Small Move*
[hours] => Array
(
[0] => Array
(
[0] => 2016-06-27 - 2016-07-03
[1] => 3.5
)
[1] => Array
(
[0] => 2016-05-30 - 2016-06-05
[1] => 9.5
)
)
)
)
我希望它看起来像这样......
Array
(
[1488] => Array
(
[project_name] => test
[hours] => Array
(
[0] => Array
(
[0] => 2016-07-11 - 2016-07-17
[1] => 37
)
[1] => Array
(
[0] => 2016-07-04 - 2016-07-10
[1] => 117
)
)
)
[2] => Array
(
[project_name] => Invoice 78554
[hours] => Array
(
[0] => Array
(
[0] => 2016-06-13 - 2016-06-19
[1] => 10
)
)
)
[3] => Array
(
[project_name] => Small Move*
[hours] => Array
(
[0] => Array
(
[0] => 2016-06-27 - 2016-07-03
[1] => 3.5
)
[1] => Array
(
[0] => 2016-05-30 - 2016-06-05
[1] => 9.5
)
)
)
)
这是我的代码......
$project_hours = array();
foreach($time_recs as $phours){
$year = date('Y');
$w = date('W', strtotime($phours['work_date']));
$time = strtotime("1 January $year", time());
$day = date('w', $time);
$time += ((7*$w)+1-$day)*24*3600;
$return[0] = date('Y/m/d', $time);
$time += 6*24*3600;
$return[1] = date('Y/m/d', $time);
$startend = $return[0]. ' - '. $return[1];
$project_hours[$phours['project_id']]['project_name'] = $phours['project_name'];
$project_hours[$phours['project_id']]['hours'][] = array(0 => $startend, 1 => (float)$phours['entry_hours']);
$project_hours[$phours['project_id']]['project_hours'][] = (float)$phours['entry_hours'];
}
foreach($project_hours as $hours) {
if (array_key_exists($hours['hours'][1], $project_hours[$hours['hours']][1])) {
$project_hours[$hours['project_name']]['time'][] += $hours['hours'][1];
}else{
$project_hours[$hours['project_name']]['time'][] = $hours['hours'][1];
}
}