Question

这个应该很简单。假设我有一个函数，我从函数中的某个包中调用了一些函数。我想自定义函数包的传递参数，以确定用户是否已将参数传递给我的函数。示例代码：

import SomePackage as sp

def myFunc(foo, bar, baz=None, xad=False):
    # some code to do some stuff...
    # then finally:
    if baz is not None:
        sp.someFunc(data=foo, method=bar, aux=baz)
    else:
        sp.someFunc(data=foo, method=bar)

有没有办法用一条整齐的Pythonic线替换最后4行？类似的东西：

def myFunc(foo, bar, baz=None, xad=False):
    # some code to do some stuff...
    # then finally:
    sp.someFunc(data=foo, method=bar, [aux=baz if baz is not None])

Answer 1

您可以使用argument unpacking执行此操作：

def func1(one, two, three):
    args = {"one": one, "two": two, "three": three}
    func2(*args)

def func2(one, two, three):
    print "one = %s, two = %s, three = %s" % (one, two, three)

if __name__ == "__main__":
    func1(one="does", two="this", three="work")

示例运行：

python foo.py
one = does, two = this, three = work

当然，您可以在传递之前修改args。

如果用户python传递，则将参数传递给函数

1 个答案: