输出如下：

Question

#The program is as below.

该程序允许用户尝试两次猜测两个彩票号码。如果用户猜测我的号码正确，用户可获得100美元，还有一次机会玩。如果在第二次机会中用户再次猜到一个号码，则用户不再获得任何号码。

import random 
guessed=False
attempts=2
while attempts > 0 and not guessed:
    lottery1= random.randint(0, 99)
    lottery2= random.randint(45,109)
    guess1 = int(input("Enter your first lottery pick : "))
    guess2 = int(input("Enter your second lottery pick : "))
    print("The lottery numbers are", lottery1, ',', lottery2)

    if guess2==lottery2 or guess1==lottery1:
        print("You recieve $100!, and a chance to play again")
    attempts-=1
    if (guess1 == lottery1 and guess2 == lottery2):
        guessed=True
        print("You got both numbers correct: you win $3,000")      
else:
    print("Sorry, no match")

输出如下：

Enter your first lottery pick : 35

Enter your second lottery pick : 45
The lottery numbers are 35 , 78
You recieve $100!, and a chance to play again
Sorry, no match

Enter your first lottery pick : 35
Enter your second lottery pick : 45
The lottery numbers are 35 , 45
You recieve $100!, and a chance to play again
You got both numbers correct: you win $3,000
Sorry, no match

我想摆脱这条线＆＃34;你收到100美元！并有机会再玩＃34;当用户正确地猜测两个数字时，如果用户猜出一个数字正确，则在第二次尝试。我希望这是有道理的

Answer 1

我假设您在此处拥有的代码段缩进与您在IDE中的缩进相同。如您所见，您的else语句没有正确缩进。所以首先你必须检查你有多少匹配，我建议你使用你的彩票号码列表，然后检查用户猜测，看看有多少匹配，这样你的代码将更灵活。如果两个数字匹配，如果没有测试，如果至少有一个匹配，如果它们都没有显示Sorry, no match消息。因此代码应如下所示：

matches = 0
lottery = [random.randint(0, 99), random.randint(45,109)]
guesses = [guess1, guess2]
for guess in guesses:
    if guess in lottery:
        matches+=1
# so now we know how many matches we have
# matches might be more than length of numbers in case you have the the  same numbers in lottery
if matches >= len(lottery):
    guessed=True
    print("You got both numbers correct: you win $3,000")
elif matches == 1:
    print("You receive $100!, and a chance to play again")
else:
    print("Sorry, no match")
    attempts-=1

希望它有用！

摆脱一些输出

输出如下：

1 个答案: