Question

我无法谷歌，并且无法理解为什么这段代码的工作方式

Python 3.5.2 (default, Sep 28 2016, 18:08:09) 
[GCC 4.2.1 Compatible Apple LLVM 8.0.0 (clang-800.0.38)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import socket
>>> s = socket.socket(socket.SOCK_DGRAM)
>>> s.connect(('127.0.0.1', 33000))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ConnectionRefusedError: [Errno 61] Connection refused
>>> s.family
<AddressFamily.AF_INET: 2>
>>> 
>>>
>>> s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
>>> s.family
<AddressFamily.AF_INET: 2>
>>> s.connect(('127.0.0.1', 33000))
>>>

编辑：

Python 3.5.2 (default, Sep 28 2016, 18:08:09) 
[GCC 4.2.1 Compatible Apple LLVM 8.0.0 (clang-800.0.38)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> s2 = socket.socket(socket.SOCK_DGRAM)
KeyboardInterrupt
>>> import socket
>>> s = socket.socket(socket.SOCK_DGRAM)
>>> s.connect(('127.0.0.1', 33000))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ConnectionRefusedError: [Errno 61] Connection refused
>>> s.family
<AddressFamily.AF_INET: 2>
>>> s.type
<SocketKind.SOCK_STREAM: 1>
>>>

看起来这是TCP套接字=）我猜Python会做一些检查并丢弃不正确的值但不提供有关该技巧的任何信息。

Answer 1

来自documentation：

socket.socket([family[, type[, proto]]])

socket.socket(socket.SOCK_DGRAM)使用SOCK_DGRAM作为家人即使这是一种类型。这会引起你所见过的奇怪问题。

Python socket.connect奇怪的行为

1 个答案: