是否可以在构造函数中设置state？

Question

我试图在构造函数中设置setState但不知何故它不起作用。

constructor(props) {
 super(props);
 this.state = {
  example: false
 }

 this.setState({example: true}) //Not doing anything

}

这两项都不起作用：

constructor(props) {
 super(props);
 this.state = {
  example: false
 }

 this.state.example = true //Not doing anything

}

我的理由是：

constructor(props) {
 super(props);
 this.state = {
  panResponders: []
 }

 let panResponders = []
 for(let i=0; i < 5; i++){
  panResponders.push(this.panResponder(i), this.state.showDraggable)
 }
 this.setState({panResponders: panResponders}) //I want to do this
}

我希望以后能够在构造函数中将状态添加到状态

修改

我在componentDidMount中尝试过第一个console.log()是一个数组但是setState()没有对它进行处理它还是空的。

  componentDidMount(){
    const {question, actions} = this.props
    this.panResponder = (number, draggables) => PanResponder.create({
        onStartShouldSetPanResponder    : () => true,
        onPanResponderMove              : Animated.event([null,{
            dx  : this.state.pan[number].x,
            dy  : this.state.pan[number].y
        }]),
        onPanResponderRelease           : (e, gesture) => {
            if(this.isDropZone(gesture)){
                this.setState({
                    showDraggable : draggables
                });
            }else{
                Animated.spring(
                    this.state.pan[number],
                    {toValue:{x:0,y:0}}
                ).start();
            }
        }
    });

    let panResponders = []
    for(let i=0; i < question.currentQuestion.antwoorden.length; i++){
      panResponders.push(this.panResponder(i), this.state.showDraggable)
    }
    console.log(panResponders) //Populated array
    console.log(this.state.panResponders) // null
    this.setState({panResponders: "panResponders"})
    console.log(this.state.panResponders) // null
  }