在工作中，我的一项任务是计算销售人员的佣金。一条规则比其他规则更具挑战性。
两个销售团队A和B共同合作，销售不同的产品。 A队可以向B队发送线索。同一客户可能会多次发送。第一次向客户（例如，引导1）*发送佣金时，将向创建该潜在客户的A团队的销售人员支付佣金。现在，客户在接下来的365天内“锁定”（从创建日期前1开始计算）。这意味着在此期间没有人可以通过发送额外的潜在客户来获得该客户的额外佣金（例如，潜在客户2和3没有佣金）。 365天过期后。可以创建新的潜在客户并获得佣金（例如，潜在客户4）。然后，客户再次被锁定365天，从创建第4天开始算起。因此，领导5没有佣金。棘手的部分是重置计算365天的日期。
'*参考表#LEADS和#DISERED结果。
我已经使用游标解决了tSQL中的问题，但我想知道是否可以使用递归CTE。我做了几次尝试，下面粘贴最好的一次。我的解决方案的问题是，我不止一次地引用递归表。我试图通过在CTE中嵌套CTE来解决这个问题。这是不允许的。我已经尝试在CTE中使用临时表，这也是不允许的。我尝试了几次重新编码CTE的递归部分，以便递归表只被引用一次，但后来我无法使逻辑工作。
我正在使用SQL 2008
IF OBJECT_ID('tempdb.dbo.#LEADS', 'U') IS NOT NULL
DROP TABLE #LEADS;
CREATE TABLE #LEADS (LEAD_ID INT, CUSTOMER_ID INT, LEAD_CREATED_DATE DATETIME, SALESPERSON_NAME varchar(20))
INSERT INTO #LEADS
VALUES (1, 1, '2013-09-01', 'Rasmus')
,(2, 1, '2013-11-01', 'Christian')
,(3, 1, '2014-01-01', 'Nadja')
,(4, 1, '2014-12-24', 'Roar')
,(5, 1, '2015-12-01', 'Kristian')
,(6, 2, '2014-01-05', 'Knud')
,(7, 2, '2015-01-02', 'Rasmus')
,(8, 2, '2015-01-08', 'Roar')
,(9, 2, '2016-02-05', 'Kristian')
,(10, 2, '2016-03-05', 'Casper')
SELECT *
FROM #LEADS;
IF OBJECT_ID('tempdb.dbo.#DISERED_RESULT', 'U') IS NOT NULL
DROP TABLE #DISERED_RESULT;
CREATE TABLE #DISERED_RESULT (LEAD_ID INT, DESIRED_COMMISION_RESULT CHAR(3))
INSERT INTO #DISERED_RESULT
VALUES (1, 'YES')
,(2, 'NO')
,(3, 'NO')
,(4, 'YES')
,(5, 'NO')
,(6, 'YES')
,(7, 'NO')
,(8, 'YES')
,(9, 'YES')
,(10, 'NO')
SELECT *
FROM #DISERED_RESULT;
WITH COMMISSION_CALCULATION AS
(
SELECT T1.*
,COMMISSION = 'YES'
,MIN_LEAD_CREATED_DATE AS COMMISSION_DATE
FROM #LEADS AS T1
INNER JOIN (
SELECT A.CUSTOMER_ID
,MIN(A.LEAD_CREATED_DATE) AS MIN_LEAD_CREATED_DATE
FROM #LEADS AS A
GROUP BY A.CUSTOMER_ID
) AS T2 ON T1.CUSTOMER_ID = T2.CUSTOMER_ID AND T1.LEAD_CREATED_DATE = T2.MIN_LEAD_CREATED_DATE
UNION ALL
SELECT T10.LEAD_ID
,T10.CUSTOMER_ID
,T10.LEAD_CREATED_DATE
,T10.SALESPERSON_NAME
,T10.COMMISSION
,T10.COMMISSION_DATE
FROM (SELECT ROW_NUMBER() OVER(PARTITION BY T5.CUSTOMER_ID ORDER BY T5.LEAD_CREATED_DATE ASC) AS RN
,T5.*
,T6.MAX_COMMISSION_DATE
,DATEDIFF(DAY, T6.MAX_COMMISSION_DATE, T5.LEAD_CREATED_DATE) AS ANTAL_DAGE_SIDEN_SIDSTE_COMMISSION
,CASE
WHEN DATEDIFF(DAY, T6.MAX_COMMISSION_DATE, T5.LEAD_CREATED_DATE) > 365 THEN 'YES'
ELSE 'NO'
END AS COMMISSION
,CASE
WHEN DATEDIFF(DAY, T6.MAX_COMMISSION_DATE, T5.LEAD_CREATED_DATE) > 365 THEN T5.LEAD_CREATED_DATE
ELSE NULL
END AS COMMISSION_DATE
FROM #LEADS AS T5
INNER JOIN (SELECT T4.CUSTOMER_ID
,MAX(T4.COMMISSION_DATE) AS MAX_COMMISSION_DATE
FROM COMMISSION_CALCULATION AS T4
GROUP BY T4.CUSTOMER_ID) AS T6 ON T5.CUSTOMER_ID = T6.CUSTOMER_ID
WHERE T5.LEAD_ID NOT IN (SELECT LEAD_ID FROM COMMISSION_CALCULATION)
) AS T10
WHERE RN = 1
)
SELECT *
FROM COMMISSION_CALCULATION;
答案 0 :(得分：0)
我已经做了一些假设，你的描述并没有像写的那样完全有意义，但是下面会达到你想要的结果：
if object_id('tempdb.dbo.#leads', 'u') is not null
drop table #leads;
create table #leads (lead_id int, customer_id int, lead_created_date datetime, salesperson_name varchar(20))
insert into #leads
values (1, 1, '2013-09-01', 'rasmus')
,(2, 1, '2013-11-01', 'christian')
,(3, 1, '2014-01-01', 'nadja')
,(4, 1, '2014-12-24', 'roar')
,(5, 1, '2015-12-01', 'kristian')
,(6, 2, '2014-01-05', 'knud')
,(7, 2, '2015-01-02', 'rasmus')
,(8, 2, '2015-01-08', 'roar')
,(9, 2, '2016-02-05', 'kristian')
,(10, 2, '2016-03-05', 'casper')
if object_id('tempdb.dbo.#disered_result', 'u') is not null
drop table #disered_result;
create table #disered_result (lead_id int, desired_commision_result char(3))
insert into #disered_result
values (1, 'yes'),(2, 'no'),(3, 'no'),(4, 'yes'),(5, 'no'),(6, 'yes'),(7, 'no'),(8, 'yes'),(9, 'yes'),(10, 'no')
with rownum
as
(
select row_number() over (order by customer_id, lead_created_date) as rn -- This is to ensure an incremantal ordering id
,lead_id
,customer_id
,lead_created_date
,salesperson_name
from #leads
)
,cte
as
(
select rn
,lead_id
,customer_id
,lead_created_date
,salesperson_name
,'yes' as commission_result
,lead_created_date as commission_window_start
from rownum
where rn = 1
union all
select r.rn
,r.lead_id
,r.customer_id
,r.lead_created_date
,r.salesperson_name
,case when r.customer_id <> c.customer_id -- If the customer ID has changed, we are at a new commission window.
then 'yes'
else case when r.lead_created_date > dateadd(d,365,c.commission_window_start) -- This assumes the window is 365 days and not one year (ie. Leap years don't add a day)
then 'yes'
else 'no'
end
end as commission_result
,case when r.customer_id <> c.customer_id
then r.lead_created_date
else case when r.lead_created_date > dateadd(d,365,c.commission_window_start) -- This assumes the window is 365 days and not one year (ie. Leap years don't add a day)
then r.lead_created_date
else c.commission_window_start
end
end as commission_window_start
from rownum r
inner join cte c
on(r.rn = c.rn+1)
)
select lead_id
,commission_result
from cte
order by customer_id
,lead_created_date;