Question

我正在编写一个离子应用程序 - 所以这是角度1.x

我有两个数字数组

var arr1 = [1,32,423,43,23,64,232,5,67,54];
var arr2 = [11,32,1423,143,123,64,2232,35,467,594];

数组32中有两个常用数字，64位。

我只是想要一些javascript来有效地返回true，如果有的话 2个数组中至少有1个常用数字。

我有以下代码

angular.forEach(arr1 , function (arr1 , count) {
              if ( inArray(arr1 , arr2) )
              {
                return true;
              }
          });

Answer 1

var arr1 = [1, 32, 423, 43, 23, 64, 232, 5, 67, 54];
var arr2 = [11, 32, 1423, 143, 123, 64, 2232, 35, 467, 594];

function hasCommonNumbers(arr1, arr2) {
  let found = false;
  for (let i = 0; i < arr1.length; i++) {
    if (arr2.indexOf(arr1[i]) !== -1) {
      found = true;
      break;
    }
  }
  return found;
}

console.log(hasCommonNumbers(arr1,arr2));

Answer 2

与ES6相比，这是微不足道的：

＆＃13;

var arr1 = [1, 32, 423, 43, 23, 64, 232, 5, 67, 54];
var arr2 = [11, 32, 1423, 143, 123, 64, 2232, 35, 467, 594];

console.log(arr1.some(i => arr2.includes(i)));

＆＃13;

Answer 3

MDN some - 当找到匹配时停止查看，返回布尔值
MDN includes - 如果item在数组中，则返回boolean to state

var arr1 = [1,32,423,43,23,64,232,5,67,54];
var arr2 = [11,32,1423,143,123,64,2232,35,467,594];

var hasDupe = arr1.some(function(val){
   return arr2.includes(val);
});

console.log(hasDupe);

如果两个数组中至少有一个，则比较两个数组以返回true

3 个答案: