我有什么解决方案可以像下面的代码那样做吗?
let tmp: NSString = data.status
let tmp1: NSString = data.process
let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch) && tmp1.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
return range.location != NSNotFound
我这样做是因为我想搜索多个字段。 谢谢
答案 0 :(得分:0)
if data.status.lowercased().contains(searchText.lowercased()) || data.process.contains(searchText) {
return true
}else {
return false
}
答案 1 :(得分:0)
如果您要查找范围,则应使用RegularExpression
代替
import Foundation
let pattern = "search"
let regexp = try! NSRegularExpression(pattern: pattern, options: NSRegularExpression.Options())
let string = "String to search in search"
regexp.enumerateMatches(in: string, options: NSRegularExpression.MatchingOptions(), range: NSMakeRange(0, string.characters.count), using: { (result, flags, stop) in
if result?.range != nil {
print("Range is \(result!.range.location)-\(result!.range.length)")
}
})