Question

我不明白构造函数是如何工作的。我试图将这些数字带入课程的主程序中，但每当我尝试在主程序上使用construtor时，它就会出现＆＃34; Class Fooditem不包含一个带有2个参数的构造函数＃34 ;.这非常混乱，因为我有一个叫public food(string name, int numberserved)的权利。我不明白为什么会出现这条消息而且我不知道如何修复它。任何帮助，将不胜感激。

class Program
    {
        static void Main(string[] args)
        {
            FoodItem firstfood = new FoodItem("Spagetti", 3);
            Console.WriteLine("The First Food is '{0}' And it serves {1}",   firstfood.Name, firstfood.NumberServed);
        }
    }

class FoodItem
    {
        string _name;       
        int _numberserved;

        public void food(string name)
        {
            _name = name;
            _numberserved = 0;
        }
        public void food(string name, int numberserved)
        {
            _name = name;
            NumberServed = numberserved;
        }

        public string Name
        {
            get
            {
                return _name;
            }
        }

        public int NumberServed
        {
            get
            {
                return _numberserved;
            }
            set
            {
                if (value > 4)
                {
                    _numberserved = 4;
                }
                else
                {
                    _numberserved = value;
                }
            }
        }
    }

Answer 1

构造函数应该与您的类具有相同的名称，并且没有返回类型：

class FoodItem
{
    string _name;       
    int _numberserved;

    public FoodItem(string name)
    {
        _name = name;
        _numberserved = 0;
    }
    public FoodItem(string name, int numberserved)
    {
        _name = name;
        NumberServed = numberserved;
    }
}

Answer 2

如果该类被调用FoodItem，那么构造函数也应该被称为FoodItem并且没有返回值：

public class FoodItem
{
    public FoodItem()
    {
        // Do stuff
    }

    public FoodItem(string name, int numberserved)
    {
        // Do stuff
    }
}

您可以使用: this构造将构造函数链接在一起。它可以以任何方式工作：

    public FoodItem()
    {
        // Do basic stuff
    }

    public FoodItem(string name, int numberserved) : this()
    {
        // Do other stuff
    }

或

    public FoodItem() : this ("defaultName", 0)
    {
    }

您的所作所为完全取决于您的申请。

Answer 3

您错误地命名了构造函数。将其更改为FoodItem，如下所示：

$.each($footerObj, function(key, value) {

    $('.footer__links').append('<ul class="footer__list"></ul>');

    var $footerList = $('.footer__list');

    $.each(value.links, function(subkey, subvalue) {

        $footerList.append('<li class="footer__item"><a class="footer__link" href="' + subvalue.url + '">' + subvalue.title + '</a></li>');

    });

});

Answer 4

我已更改了您的代码，现在可以使用了。

class Program
    {
        static void Main(string[] args)
        {
            FoodItem firstfood = new FoodItem("Spagetti", 3);
            Console.WriteLine("The First Food is '{0}' And it serves {1}",   firstfood.Name, firstfood.NumberServed);
        }
    }

class FoodItem
    {
        string _name;       
        int _numberserved;

        public void food(string name)  
        public FoodItem()
        {
            _name = name;
            _numberserved = 0;
        }
        public void food(string name, int numberserved)
        public FoodItem(string name, int numberserved)

        {
            _name = name;
            NumberServed = numberserved;
        }

        public string Name
        {
            get
            {
                return _name;
            }
        }

        public int NumberServed
        {
            get
            {
                return _numberserved;
            }
            set
            {
                if (value > 4)
                {
                    _numberserved = 4;
                }
                else
                {
                    _numberserved = value;
                }
            }
        }
    }

请告诉我您的想法或反馈。

感谢 KARTHIK

c＃带参数的构造函数如何工作？

4 个答案: