Question

您好我在尝试遍历类列表时遇到一些麻烦，以便打印出该类实例所持有的特定值。我的程序编译但是它没有打印任何东西，我也尝试过在玩家列表中拥有＆＃34; player.player＆＃34;在for循环中，我也得到了相同的结果。非常感谢任何帮助。

我的主要功能

class main:

if __name__ == '__main__':

    while True:

        print("Please Select An Option Below:")
        print("1 - Create Player:")
        print("2 - List Players:")
        print("3 - Create Team:")
        print("4 - Sell Player:")
        print("5 - Buy Player:")
        x = raw_input("Please select a option: \n")

        playerList = []

        if(x == '1'):

            import Player
            p1 = Player.player()
            pname = raw_input("Please Enter A Player Name \n")
            page = raw_input("Please Enter A Player Age \n")
            pwage = raw_input("Please Enter A Player Wage \n")
            pteam = raw_input("Please Enter A Player Team \n")
            p1.pname = pname
            p1.page = page
            p1.pwage = pwage
            p1.pteam = pteam
            playerList.append(p1)
            continue

        if(x == '2'):
            for p1 in playerList:
                print(p1.pname)
            continue

我的播放器课程

class player(object):

    @property
    def pname(self):
        return self.pname

    @pname.setter
    def pname (self, value):
        pass

    @property
    def page(self):
        return self.page

    @page.setter
    def page (self, value):
        pass

    @property
    def pwage(self):
        return self.pwage

    @pwage.setter
    def pwage(self, value):
        pass

    @property
    def pteam(self):
        return self.pteam

    @pteam.setter
    def pteam(self, value):
        pass

---- -----更新

class main:

    if __name__ == '__main__':

        while True:

            print("Please Select An Option Below:")
            print("1 - Create Player:")
            print("2 - List Players:")
            print("3 - Create Team:")
            print("4 - Sell Player:")
            print("5 - Buy Player:")
            x = raw_input("Please select a option: \n")

            playerList = []

            if(x == '1'):

                import Player
                nplayer = Player.player()
                nplayer.set_name(raw_input("test\n"))
                playerList.append(nplayer)
                continue

            if(x == '2'):
                 for player in playerList:
                     print(player.get_name)
                 continue

class player(object):

    __name = ""

    @property
    def get_name(self):
        return self.__name

    def set_name(self, name):
        self.__name = name

Answer 1

当你写p1.pname = pname时，会调用setter。但是，您不会在setter中执行任何操作。因此，当稍后调用getter时，它没有任何东西可以返回。

要使getter和setter在python中工作，你需要做这样的事情：

class player(object):
    @property
    def pname(self):
        return self._pname

    @pname.setter
    def pname (self, value):
        self._pname = value

Answer 2

非常感谢那些帮助它的人，我的问题是由于没有正确设置setter / getter而导致的，因为我在显示菜单选项中使用了我的数组，导致它将类的实例发送到另一个列表。 / p>

Identity

Python迭代一个类对象列表并提取一个值

2 个答案: