蓝J字对撞机第2部分

Question

早些时候，我在单词对撞机程序中专门针对animate方法提出了一个问题。这个程序的目的是当两个单词碰撞时，单词会爆炸，每个单独的角色将随机散布在屏幕上。以下是我的程序的代码;

/**
 * Write a description of class WordCollider here.
 * 
 * @author 
 * @version 
 */

public class WordCollider
{
    // instance variables - replace the example below with your own
    private Text word1;
    private Text word2;
    // the characters contained in word1
    private Text[] charWord1;
    // the characters contained in word2
    private Text[] charWord2;

    /**
     * Constructor for objects of class WordCollider
     */
    public WordCollider(String w1, String w2)
    {
        // initialise instance variables
        word1 = new Text(w1);
        word1.randomizePosition();
        word1.changeColor("green");
        word1.changeSize(48);
        word1.makeVisible();
        word2 = new Text(w2);
        word2.randomizePosition();
        word2.changeColor("orange");
        word2.changeSize(48);
        word2.makeVisible();
        charWord1 = new Text[w1.length()];
        charWord2 = new Text[w2.length()];
        fillChars(charWord1, w1);
        fillChars(charWord2, w2);
    }

    private void fillChars(Text[] a, String w) {
        char[] cs = w.toCharArray();
        for (int i=0; i<a.length; i++) {
            a[i] = new Text(""+cs[i]);
            a[i].changeSize(48);
            a[i].changeColor("red");
        }
    }

    /**
     * Randomize the position of the two words repeatedly and stop
     * when the bounding box of the two words overlaps.
     */
    public void animate()
    {
        while(checkOverlap() == false){
            word1.randomizePosition();
            word2.randomizePosition();
        }

        while(checkOverlap() == true){ 
            word1.makeInvisible();
            word2.makeInvisible();
        }

        for(int i = 0; i < charWord1.length; i++){
            word1.makeVisible();
            word1.randomizePosition();
        }

        for(int i = 0; i < charWord2.length; i++){
            word2.makeVisible();
            word2.randomizePosition();
        }
    }

    /**
     * erase the words and any other characters on the display
     */
    public void clearDisplay() {
        word1.makeInvisible();
        word2.makeInvisible();
    }

    /**
     * check if the bounding box of the two words overlaps.
     * @return true when the words overlap and false otherwise.
     */
    private Boolean checkOverlap() {

        if (word2.getXPosition() < word1.getXPosition() + word1.getTextWidth()){
            return true;
        }

        if (word1.getXPosition() > word2.getXPosition() + word2.getTextWidth()){
            return true;
        }

        if (word2.getYPosition() < word1.getYPosition() - word1.getTextHeight()){
            return true;
        }

        if (word1.getYPosition() > word2.getYPosition() - word2.getTextHeight()){
            return true;
        }

        if (word2.getXPosition() < word1.getXPosition() + word1.getTextWidth() && word1.getXPosition() > word2.getXPosition() + word2.getTextWidth()){
            return true;
        }

        if (word2.getYPosition() < word1.getYPosition() - word1.getTextHeight() && word1.getYPosition() > word2.getYPosition() - word2.getTextHeight()){
            return true;
        }
        return false;
    }
}

animate方法的目的是，如果checkOverlap为false，单词将在屏幕上随机化，而如果checkOverlap为true，那么我想让单词不可见并将字母分散在屏幕上

清晰显示方法的目的只是让屏幕上的单词不可见。

checkOverlap方法的目的是检查两个单词是否重叠，如果它们重叠，则return语句将为true，如果它们不重叠，则返回false

我如何解决这个问题，以便我的计划有效？