在这里,我有一个名为mainArray
的主阵列。在这个数组中我添加了多个用户列表。它可以增加。我可以从这个mainarray
创建许多组,例如group1,group2等等。我的要求是,我想过滤mainArray
中尚未添加到组中的对象。
Array main,
var mainArray = [{
userId: "M000001",
name: "Jhon",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
组,
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
加入群组ID
var joinedGroupIds = ["M000004", "M000005", "M000002", "M000003", "M000001"];
我想要的输出,
var result = [{
{
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}
}];
我的javascript代码,
var joinGroup, joinedGroupIds = [];
joinGroup = group1.concat(group2);
Concatinated group id,
joinedGroupIds.map(function(el){
joinedGroupIds.push(el.userId);
});
从主数组中过滤对象
var result = mainArray.filter(function(item) {
if (joinedGroupIds.indexOf(item.userId) !== -1) return item;
});
答案 0 :(得分:2)
indexOf
无法在内部数组中搜索。使用.findIndex
var result = mainArray.filter(function(x) {
return joinedGroup.findIndex(function(y) {
return y.userId === x.userId
}) === -1
})
var mainArray = [{
userId: "M000001",
name: "Jhon",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
var joinedGroup = group1.concat(group2);
var result = mainArray.filter(function(x) {
return joinedGroup.findIndex(function(y) {
return y.userId === x.userId
}) === -1
})
console.log(result)

userIds
保存在joinedGroup var joinedGroup = [];
group1.forEach(x => joinedGroup.push(x.userId))
group2.forEach(x => joinedGroup.push(x.userId))
var result = mainArray.filter(function(x) {
return joinedGroup.indexOf(x.userId) === -1
})
var mainArray = [{
userId: "M000001",
name: "Jhon",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
var joinedGroup = [];
group1.forEach(x => joinedGroup.push(x.userId))
group2.forEach(x => joinedGroup.push(x.userId))
var result = mainArray.filter(function(x) {
return joinedGroup.indexOf(x.userId) === -1
})
console.log(result)

答案 1 :(得分:1)
创建组中现有项目的索引,然后使用它来过滤原始数组。
ES6(因为你正在使用React):
>>> a = [[1,2,3],[1,2,3],3,5,6]
>>> [y for x in a for y in (x if isinstance(x, list) else [x])]
[1, 2, 3, 1, 2, 3, 3, 5, 6]
使用lodash:
const filterByGroups = (arr, ...groups) => {
// create a Set of existing userId in the groups
const exitingItems = new Set(
[].concat([], ...groups).map(({ userId }) => userId)
);
// filter from the array all items that their userId exists in the Set
return arr.filter(({ userId }) => !exitingItems.has(userId));
};
var mainArray = [{
userId: "M000001",
name: "Jhon",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
const result = filterByGroups(mainArray, group1, group2);
console.log(result);
function filterByGroups(arr) {
var existingItems = _([].slice.call(arguments, 1))
.flatten()
.keyBy('userId')
.value();
return arr.filter(function(item) {
return !existingItems[item.userId];
});
}
var mainArray = [{
userId: "M000001",
name: "Jhon",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
var result = filterByGroups(mainArray, group1, group2);
console.log(result);
答案 2 :(得分:0)
您可以使用differenceWith方法并完成此操作。
let comparator = (a, b) => JSON.stringify(a) === JSON.stringify(b);
let result = _.differenceWith(mainArray, group1.concat(group2), comparator);
这是工作解决方案。
var mainArray = [{
userId: "M000001",
name: "John",
companyId: "C0000021"
}, {
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}, {
userId: "M000006",
name: "Roldan",
companyId: "C0000026"
}, {
userId: "M000007",
name: "Mike",
companyId: "C0000027"
}, {
userId: "M000008",
name: "Mia",
companyId: "C0000028"
}];
var group1 = [{
userId: "M000004",
name: "Sean",
companyId: "C0000024"
}, {
userId: "M000005",
name: "Paul",
companyId: "C0000025"
}];
var group2 = [{
userId: "M000002",
name: "Leon",
companyId: "C0000022"
}, {
userId: "M000003",
name: "Thomas",
companyId: "C0000023"
}, {
userId: "M000001",
name: "John",
companyId: "C0000021"
}];
let comparator = (a, b) => JSON.stringify(a) === JSON.stringify(b);
let result = _.differenceWith(mainArray, group1.concat(group2), comparator);
console.log(result);

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