Question

我有以下密钥数组：

var keys = [{userId: "333"}, {userId: "334"}]

这个对象数组：

var users = [
{id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""}
]

我需要通过使用users Array [反向结果]对其进行过滤来更改我的keys Array。

不能弄明白，得到所有的答案！（js，jquery，angular）

任何？

Answer 1

您可以使用filter()和find()。

var users = [
{id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""}
]
var keys = [{userId: "333"}, {userId: "334"}]

var result = users.filter(function(o) {
  return !keys.find(function(e) {
    return e.userId == o.id
  })
})

console.log(result)

Answer 2

您可以拥有id的数组，然后您可以在此列表中查看可用性

＆＃13;

var users = [
{id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""}
]

var keys = [{userId: "333"}, {userId: "334"}]

var idList = keys.map(function(x){ return x.userId});
var r = users.filter(function(x){
  return idList.indexOf(x.id) < 0
})

console.log(r)

＆＃13;

Answer 3

您可以使用哈希表进行过滤。

＆＃13;

var keys = [{ userId: "333" }, { userId: "334" }],
    users = [{ id: "333", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "334", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "335", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "336", firstName: "", lastName: "", idCard: "", birthDate: "" }],
    filtered = users.filter(function (a) {
        return !this[a.id];
    }, keys.reduce(function (r, a) {
        r[a.userId] = true;
        return r;
    }, Object.create(null)));

console.log(filtered);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

使用keys数组过滤对象数组[逆]

3 个答案: