我有一个玩扑克游戏的任务。它的作用如下：它生成5个数字（0到52之间）。这五个数字将根据其值转换为符号和实际卡片值。我需要允许用户更改最多4张牌，而不是两次给他相同的牌。我的问题是：当他改变第一张牌时它会顺利进行，但如果他决定改变第二张牌，那么第一张牌也会改变。以下是代码，并提前感谢您的帮助（如果您不理解，请注释法语请告诉我）（同时忽略未使用的方法，因为我还没有完成）：
package pkgtp2;
import java.util.*;
public class TP2 {
static int[] cards = new int[5];
static int[] sortes = new int[5];
static int balance = 100;
static int h = 0;
public static void Initialiser(boolean[] pack) {
pack = new boolean[52];
}
public static void Regles() {
System.out.println("************** " + " AUCUNE COMBINAISON = -10$");
System.out.println("*Jeu de Poker* " + " 1 PAIRE = 0$");
System.out.println("************** " + " 2 PAIRES = 20$");
System.out.println(" " + " BRELAN<3> = 35$");
System.out.println(" " + " SUITE = 50$");
System.out.println(" " + " FULL = 75$");
System.out.println(" " + " COULEUR = 100$");
System.out.println(" " + " CARRÉ = 150$");
System.out.println(" " + " QUINTE ROYALE = 500$");
System.out.println(" Vous avez :" + balance + " $");
}
public static void findcards(int[] cards, boolean[] pack) {
System.out.println();
char symboles[] = {'♥', '♦', '♣', '♠'};
String valeurs[] = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};
for (int i = 0; i < cards.length; i++) {
switch (cards[i] / 13) {
case 0:
System.out.print(symboles[0]);
break;
case 1:
System.out.print(symboles[1]);
break;
case 2:
System.out.print(symboles[2]);
break;
case 3:
System.out.print(symboles[3]);
break;
}
switch (cards[i] % 13 + 1) {
case 1:
System.out.print(valeurs[0]);
break;
case 2:
System.out.print(valeurs[1]);
break;
case 3:
System.out.print(valeurs[2]);
break;
case 4:
System.out.print(valeurs[3]);
break;
case 5:
System.out.print(valeurs[4]);
break;
case 6:
System.out.print(valeurs[5]);
break;
case 7:
System.out.print(valeurs[6]);
break;
case 8:
System.out.print(valeurs[7]);
break;
case 9:
System.out.print(valeurs[8]);
break;
case 10:
System.out.print(valeurs[9]);
break;
case 11:
System.out.print(valeurs[10]);
break;
case 12:
System.out.print(valeurs[11]);
break;
case 13:
System.out.print(valeurs[12]);
break;
}
System.out.println();
}
}
public static void inicartes(int[] cards, boolean[] pack) {
Random give = new Random();
for (int i = 0; i < cards.length; i++) {
do {
cards[i] = give.nextInt(52);
} while (pack[cards[i]]);
pack[cards[i]] = true;
System.out.println(cards[i]);
}
}
public static void Mélanger() {
}
public static void Afficher5cartes() {
}
public static void changecards(int[] cards, boolean[] pack) {
Scanner read = new Scanner(System.in);
int cardchange;
Random give = new Random();
System.out.println("Veuillez entrer un chiffre de 1 a 5 correspondant aux"
+ "cartes que vous voulez changer (vous pouvez changer au plus 4 cartes). Si vous voulez conserver vos cartes, entrez '0' ");
cardchange = read.nextInt();
do {
if (cardchange < 0 || cardchange > 5) {
do {
System.out.println("Erreur, veuillez entrer un chiffre de 1 a 5 correspondant aux "
+ " cartes que vous voulez changer (vous pouvez changer au plus 4 cartes). Entrez '0' lorsque vos désirez garder vos cartes ");
cardchange = read.nextInt();
} while (cardchange < 0 || cardchange > 5);
} else if (cardchange > 0 && cardchange <= 5) {
System.out.println("\nVoici votre nouvelle main");
for (int i = 0; i < cards.length; i++) {
do {
cards[cardchange - 1] = give.nextInt(52);
} while (pack[cards[cardchange - 1]]);
pack[cards[i]] = true;
System.out.println(cards[i]);
}
h++;
System.out.println("");
cardchange = read.nextInt();
}
} while (h < 4 && cardchange <= 5 && cardchange > 0);
}
public static void EvalJeu() {
}
public static void Afficher$() {
}
public static void main(String[] args) {
boolean pack[] = new boolean[52];
Regles();
inicartes(cards, pack);
findcards(cards, pack);
changecards(cards, pack);
}
}
答案 0 :(得分：0)
问题是你不必要地循环。您的要求是只改变某个位置。所以只改变那个。请参阅下面的代码。
public static void changecards(int[] cards, boolean[] pack) {
Scanner read = new Scanner(System.in);
int cardchange;
Random give = new Random();
System.out.println();
cardchange = -1;
for (int i = 0; i < 5; i++) {
System.out.println("\n\nTurn: " + i + " - Enter the card position that you want to change?");
while (cardchange < 0 || cardchange > 5) {
System.out.println("Enter a card number between 1 and 5; Enter 0 if you don't want to "
+ "change anything.");
cardchange = read.nextInt();
}
if (cardchange == 0) {
System.out.println("Turn skipped nothing will be changed.");
} else {
System.out.print("Your card number" + cardchange + " will be changed to ");
cards[cardchange - 1] = give.nextInt(52);
System.out.println(cards[cardchange - 1]);
}
cardchange = -1;
System.out.println("\n\nYour new cards are : ");
for (int card : cards) {
System.out.print(card + "\t");
}
findcards(cards,pack);
}
}
输出如下。
************** AUCUNE COMBINAISON = -10$
*Jeu de Poker* 1 PAIRE = 0$
************** 2 PAIRES = 20$
BRELAN<3> = 35$
SUITE = 50$
FULL = 75$
COULEUR = 100$
CARRÉ = 150$
QUINTE ROYALE = 500$
Vous avez :100 $
51 3 22 34 35
♠K ♥4 ♦10 ♣9 ♣10
Turn: 0 - Enter the card position that you want to change?
Enter a card number between 1 and 5; Enter 0 if you don't want to change anything.
1
Your card number1 will be changed to 40
Your new cards are :
40 3 22 34 35
♠2 ♥4 ♦10 ♣9 ♣10
Turn: 1 - Enter the card position that you want to change?
Enter a card number between 1 and 5; Enter 0 if you don't want to change anything.
0
Turn skipped nothing will be changed.
Your new cards are :
40 3 22 34 35
♠2 ♥4 ♦10 ♣9 ♣10
Turn: 2 - Enter the card position that you want to change?
Enter a card number between 1 and 5; Enter 0 if you don't want to change anything.
2
Your card number2 will be changed to 19
Your new cards are :
40 19 22 34 35
♠2 ♦7 ♦10 ♣9 ♣10
Turn: 3 - Enter the card position that you want to change?
Enter a card number between 1 and 5; Enter 0 if you don't want to change anything.
2
Your card number2 will be changed to 50
Your new cards are :
40 50 22 34 35
♠2 ♠Q ♦10 ♣9 ♣10
Turn: 4 - Enter the card position that you want to change?
Enter a card number between 1 and 5; Enter 0 if you don't want to change anything.
4
Your card number4 will be changed to 48
Your new cards are :
40 50 22 48 35
♠2 ♠Q ♦10 ♠10 ♣10