Question

在d3的有向图的this example中，我们可以看到图形在开始时被转换为稳定状态。

我想在开头直接显示稳定图（即隐藏转换部分）。有谁知道怎么做？

Answer 1

如果你想要一个静态的力导向图，而不是在每个滴答处重新定位节点和链接，你必须让模拟运行固定的次数，然后在结束时显示它：

force.start();
for (var i = 300; i > 0; --i) force.tick();//runs 300 times
force.stop();

幻数300有一个原因：根据API，

模拟开始时的自然滴答数是⌈log（alphaMin）/ log（1 - alphaDecay）⌉;默认情况下，这是300。

此for循环位于setTimeout内，以及绘制SVG中元素的代码部分。

这是您更新的Bin：https://jsbin.com/nawapigubo/1/edit?html,output

这是一个SO片段演示：

＆＃13;

<style>

.link {
  fill: none;
  stroke: #666;
  stroke-width: 1.5px;
}

#licensing {
  fill: green;
}

.link.licensing {
  stroke: green;
}

.link.resolved {
  stroke-dasharray: 0,2 1;
}

circle {
  fill: #ccc;
  stroke: #333;
  stroke-width: 1.5px;
}

text {
  font: 10px sans-serif;
  pointer-events: none;
  text-shadow: 0 1px 0 #fff, 1px 0 0 #fff, 0 -1px 0 #fff, -1px 0 0 #fff;
}

</style>
<body>
<script src="//d3js.org/d3.v3.min.js"></script>
<script>

// http://blog.thomsonreuters.com/index.php/mobile-patent-suits-graphic-of-the-day/
var links = [
  {source: "Microsoft", target: "Amazon", type: "licensing"},
  {source: "Microsoft", target: "HTC", type: "licensing"},
  {source: "Samsung", target: "Apple", type: "suit"},
  {source: "Motorola", target: "Apple", type: "suit"},
  {source: "Nokia", target: "Apple", type: "resolved"},
  {source: "HTC", target: "Apple", type: "suit"},
  {source: "Kodak", target: "Apple", type: "suit"},
  {source: "Microsoft", target: "Barnes & Noble", type: "suit"},
  {source: "Microsoft", target: "Foxconn", type: "suit"},
  {source: "Oracle", target: "Google", type: "suit"},
  {source: "Apple", target: "HTC", type: "suit"},
  {source: "Microsoft", target: "Inventec", type: "suit"},
  {source: "Samsung", target: "Kodak", type: "resolved"},
  {source: "LG", target: "Kodak", type: "resolved"},
  {source: "RIM", target: "Kodak", type: "suit"},
  {source: "Sony", target: "LG", type: "suit"},
  {source: "Kodak", target: "LG", type: "resolved"},
  {source: "Apple", target: "Nokia", type: "resolved"},
  {source: "Qualcomm", target: "Nokia", type: "resolved"},
  {source: "Apple", target: "Motorola", type: "suit"},
  {source: "Microsoft", target: "Motorola", type: "suit"},
  {source: "Motorola", target: "Microsoft", type: "suit"},
  {source: "Huawei", target: "ZTE", type: "suit"},
  {source: "Ericsson", target: "ZTE", type: "suit"},
  {source: "Kodak", target: "Samsung", type: "resolved"},
  {source: "Apple", target: "Samsung", type: "suit"},
  {source: "Kodak", target: "RIM", type: "suit"},
  {source: "Nokia", target: "Qualcomm", type: "suit"}
];

var nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function(link) {
  link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
  link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});

var width = 960,
    height = 500;

var force = d3.layout.force()
    .nodes(d3.values(nodes))
    .links(links)
    .size([width, height])
    .linkDistance(60)
    .charge(-300)
    .on("tick", tick);

var svg = d3.select("body").append("svg")
    .attr("width", width)
    .attr("height", height);
  
  var path = svg.append("g").selectAll("path")
    .data(force.links())
  .enter().append("path");
  
  var circle = svg.append("g").selectAll("circle")
    .data(force.nodes())
  .enter().append("circle");
  
  var text = svg.append("g").selectAll("text")
    .data(force.nodes())
  .enter().append("text");
  
  setTimeout(function(){
    
  force.start();
  for (var i = 300; i > 0; --i) force.tick();
  force.stop();

// Per-type markers, as they don't inherit styles.
svg.append("defs").selectAll("marker")
    .data(["suit", "licensing", "resolved"])
  .enter().append("marker")
    .attr("id", function(d) { return d; })
    .attr("viewBox", "0 -5 10 10")
    .attr("refX", 15)
    .attr("refY", -1.5)
    .attr("markerWidth", 6)
    .attr("markerHeight", 6)
    .attr("orient", "auto")
  .append("path")
    .attr("d", "M0,-5L10,0L0,5");


    path.attr("class", function(d) { return "link " + d.type; })
    .attr("marker-end", function(d) { return "url(#" + d.type + ")"; });


    circle.attr("r", 6)
    .call(force.drag);


    text.attr("x", 8)
    .attr("y", ".31em")
    .text(function(d) { return d.name; });
    
  }, 100)

// Use elliptical arc path segments to doubly-encode directionality.
function tick() {
  path.attr("d", linkArc);
  circle.attr("transform", transform);
  text.attr("transform", transform);
}

function linkArc(d) {
  var dx = d.target.x - d.source.x,
      dy = d.target.y - d.source.y,
      dr = Math.sqrt(dx * dx + dy * dy);
  return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
}

function transform(d) {
  return "translate(" + d.x + "," + d.y + ")";
}

</script>

＆＃13;

（改变代码的来源：来自Mike Bostock的this example）

在开头隐藏图形的转换

1 个答案: