Question

我遇到了问题

前3个小时的停车费为每小时3美元，每增加一小时，您需要支付1美元，24小时的费用为30美元，但您可以停留超过24小时。我不知道如何解决小时＆gt; 24，就像汽车停留37小时或更长时间一样。我认为必须使用模数，不幸的是我无法使用它。任何帮助??

        if (hours >= 24) {
            price = 30;
            price += (hours - 3) % 1; //should the mod even go here?
        } else if (hours < 24 && hours > 3) {
            price = 9;
            price += (hours - 3) * 1;
        } else {
            price = hours * 3;
        }
        System.out.println("Hours: " + hours + " Price: " + price);

Answer 1

根据您的规范，它应该像以下一样简单：

    price = Math.min(hours, 3) * 3 + Math.max(hours - 3, 0) * 1;
    System.out.println("Hours: " + hours + " Price: " + price);

更新

    price = (hours / 24) * 30 + Math.min(hours % 24, 3) * 3 + Math.max(hours % 24 - 3, 0) * 1;

Answer 2

这有效：

if (hours >= 24) {
    price = (hours / 24)*30;
    int h = hours%24;
    int h4 = Math.min(h, 3)*2;
    price += h4 +((hours)%24);

} else if (hours < 24 && hours > 3) {
    price = 9;
    price += (hours - 3) * 1;
} else {
    price = hours * 3;
}
System.out.println("Hours: " + hours + " Price: " + price);

Answer 3

修改@ bohuss的解决方案以解决问题超过24小时：

private static int calculatePrice(final int hours) {
    // find number of days [where 1 day is 24 hours]
    final int days = hours / 24;
    // calculate price based on 1 day's fixed price as $30
    int price = 30 * days;
    // find remaining hours
    final int remainingHours = hours % 24;
    // calculate price for remaining hours and add to price for entire days.
    price += Math.min(remainingHours, 3) * 3 + Math.max(remainingHours - 3, 0) * 1;
    // return total price
    return price;
}

示例输入/输出

Hours: 0 Price: 0
Hours: 1 Price: 3
Hours: 2 Price: 6
Hours: 3 Price: 9
Hours: 4 Price: 10
Hours: 5 Price: 11
Hours: 6 Price: 12
...
Hours: 22 Price: 28
Hours: 23 Price: 29
Hours: 24 Price: 30
Hours: 25 Price: 33
Hours: 26 Price: 36
Hours: 27 Price: 39
Hours: 28 Price: 40

Answer 4

if(hours > 0) {
  if(hours > 3 && hours < 24) {
    price = 3 + hours;
  }
  if(hours >= 24) {
    price = 30;
  }
}

请注意，如果停车的人员在24小时后仍然按每小时1美元收费，那么：

if(hours > 0) {
  if(hours > 3 && hours < 24) {
    price = 3 + hours;
  }
  if(hours >= 24) {
    price = 30 + hours - 24;
  }
}

解决停车场费用

4 个答案: