这是我的代码:
final Intent intent = new Intent(this, SelectWidgetActivity.class);
startActivityForResult(intent, REQUEST_CREATE_APPWIDGET);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK ) {
String selectedName = data.getStringExtra(SelectWidgetActivity.SELECTED_WIDGET);
if(!mAppWidgetManager.bindAppWidgetIdIfAllowed(appWidgetId, info.provider)) {
Intent bindIntent = new Intent(AppWidgetManager.ACTION_APPWIDGET_BIND);
bindIntent.putExtra(AppWidgetManager.EXTRA_APPWIDGET_ID, appWidgetId);
bindIntent.putExtra(AppWidgetManager.EXTRA_APPWIDGET_PROVIDER, info.provider);
bindIntent.putExtra(SelectWidgetActivity.SELECTED_WIDGET, selectedName);
startActivityForResult(bindIntent, REQUEST_BIND_APPWIDGET);
}
}
}
我在第一次调用startActivityForResult时放置了String,在第二次调用时我试图获取相同的字符串,但是得到null。例如,在第一次调用selectedName =“Calendar”时,第二次调用onActivityResult()selectedName = null
有什么想法吗?
答案 0 :(得分:3)
你必须检查你在拨打电话时发送的onActivityResult中的requestCode
startActivityForResult(intent, REQUEST_CREATE_APPWIDGET);
试试这个
if (requestCode == REQUEST_CREATE_APPWIDGET && resultCode == Activity.RESULT_OK) {
//do your work here;
}