Question

您好我有两个表以下列方式相关：

Table1
gene goterms
ape   1a
ape   1b
ape   1c
boy   2a
boy   1a
cat   1a
cat   1c

Table2
gene gene count
ape  ape   3
ape  boy   1
ape  cat   2
boy  ape   1
boy  boy   2
boy  cat   1  
cat  ape   2
cat  boy   1
cat  cat   2

现在，我需要与table2的第二行对应的值 =（计数）/（表1中的猿数+表1中的男孩数） - 计数

[ape boy 1]行

，值= 1 /（（3 + 2） - 1）= 0.25

类似于table2中的所有其他行。

输出必须类似于

表3 基因基因计数猿猿3 1 猿男孩1 .25 猿猫2.5 男孩猿1 .25 男孩男孩2 1 男孩猫1 .2 猫猿2 .5 猫男孩1.2 猫猫2 1

我需要一个sql查询，我试图在很多方面，但徒劳无功。

谢谢...

Answer 1

SELECT基因，gene2，count，count /（（SELECT count（）FROM Table1 t1 在哪里t2.gene = t1.gene）+（SELECT count（）FROM Table1 t1 WHERE t2.gene2 = t1.gene） - count）作为值来自Table2 t2

输出：

gene    gene2   count   value
ape     ape     3       1.0000
ape     boy     1       0.2500
ape     cat     2       0.6667
boy     ape     1       0.2500
boy     boy     2       1.0000
boy     cat     1       0.3333
cat     ape     2       0.6667
cat     boy     1       0.3333
cat     cat     2       1.0000

Answer 2

表2中有重复的列名。假设表2的第一列是“基因”而第二列是“gene2”：

Select *
    , [Count]
        / ( Coalesce(Gene1.Total,0) + Coalesce(Gene2.Total,0) - Coalesce(Table2.Count,0))
From Table2
    Left Join (
                Select T1.gene, Count(*) As Total
                From Table1 As T1
                Group By T1.gene
                ) As Gene1
            On Gene1.gene = Table2.gene
    Left Join (
                Select T2.gene, Count(*) As Total
                From Table1 As T2
                Group By T2.gene
                ) As Gene2
            On Gene2.gene = Table2.gene2
Where ( Coalesce(Gene1.Total,0) + Coalesce(Gene2.Total,0) - Coalesce(Table2.Count,0)) > 0

当然，如果您有大量数据，这不会是世界上最快的查询。

使用SQL Server 2008，你可以使用像这样的公用表表达式来编写它更清晰：

With CountByGene As
    (
    Select T1.gene, Count(*) As Total
    From Table1 As T1
    Group By T1.gene
    )
Select *
    , [Count]
        / ( Coalesce(Gene1.Total,0) + Coalesce(Gene2.Total,0) - Coalesce(Table2.Count,0))
From Table2
    Left Join CountByGene As Gene1
        On Gene1.gene = Table2.gene
    Left Join CountByGene As Gene2
        On Gene2.gene = Table2.gene2
Where ( Coalesce(Gene1.Total,0) + Coalesce(Gene2.Total,0) - Coalesce(Table2.Count,0)) > 0

Answer 3

SELECT gene, count(*) AS value FROM Table1 GROUP BY gene;将为您提供表1中每个基因的计数。

SELECT value FROM ( SELECT gene, count(*) as value FROM Table1 GROUP BY gene; ) WHERE gene = 'boy';将为您提供子选择语句中的值。

这听起来像是家庭作业所以我只是给出这个答案作为暗示。

Answer 4

SELECT gene，gene2，count，count /（（SELECT count（）FROM Table1 t1 WHERE t2.gene = t1.gene）+（SELECT count（）FROM Table1 t1 WHERE t2.gene2 = t1.gene） - count）as calc FROM Table2 t2

用于从两个表计算值的SQL查询

4 个答案: