Question

我有来自两个表的查询...

货物以树木帐户形式存在的第一个表....

销售与第一张表相关联的第二张表。

例如，现在我有了第一张表。

问题需要排序查询..

我得到的汽车是他们的条件......电子设备的状况

表二。

使用附件，我想创建一个查询。

数据库脚本：

USE [To_Test]
GO
/****** Object:  Table [dbo].[Items]    Script Date: 11/10/1438 05:54:35 م ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Items](
    [Id_ItemS] [int] NOT NULL,
    [Name_ar] [nvarchar](50) NULL,
    [Number_Id] [int] NULL,
    [Basic] [bit] NULL,
 CONSTRAINT [PK_Items] PRIMARY KEY CLUSTERED 
(
    [Id_ItemS] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Sell_items](
    [Id_Sell] [int] IDENTITY(1,1) NOT NULL,
    [Id_items] [int] NULL,
    [price] [money] NULL,
 CONSTRAINT [PK_Sell_items] PRIMARY KEY CLUSTERED 
(
    [Id_Sell] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

GO
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (1, N'Cars', NULL, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (2, N'electronics', NULL, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (3, N'Toyota', 1, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (4, N'Nissan', 1, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (5, N'Camry', 3, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (6, N'2015', 5, 0)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (7, N'2016', 5, 0)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (8, N'2017', 5, 0)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (9, N'TV', 2, 1)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (10, N'LG', 9, 0)
INSERT [dbo].[Items] ([Id_ItemS], [Name_ar], [Number_Id], [Basic]) VALUES (11, N'Samsung', 9, 0)
SET IDENTITY_INSERT [dbo].[Sell_items] ON 

INSERT [dbo].[Sell_items] ([Id_Sell], [Id_items], [price]) VALUES (1, 11, 2500.0000)
INSERT [dbo].[Sell_items] ([Id_Sell], [Id_items], [price]) VALUES (2, 10, 2300.0000)
INSERT [dbo].[Sell_items] ([Id_Sell], [Id_items], [price]) VALUES (3, 6, 20000.0000)
INSERT [dbo].[Sell_items] ([Id_Sell], [Id_items], [price]) VALUES (4, 7, 270000.0000)
SET IDENTITY_INSERT [dbo].[Sell_items] OFF
ALTER TABLE [dbo].[Items]  WITH CHECK ADD  CONSTRAINT [FK_Items_Items1] FOREIGN KEY([Number_Id])
REFERENCES [dbo].[Items] ([Id_ItemS])
GO
ALTER TABLE [dbo].[Items] CHECK CONSTRAINT [FK_Items_Items1]
GO
ALTER TABLE [dbo].[Sell_items]  WITH CHECK ADD  CONSTRAINT [FK_Sell_items_Items] FOREIGN KEY([Id_items])
REFERENCES [dbo].[Items] ([Id_ItemS])
GO
ALTER TABLE [dbo].[Sell_items] CHECK CONSTRAINT [FK_Sell_items_Items]
GO

视图

WITH Recursive_CTE AS (
SELECT        Items.Id_ItemS, Items.Name_ar, Items.Number_Id, 1 AS RecursionLevel, CAST(Items.Id_ItemS AS varchar(100)) AS Hierarchy, Sell_items.Id_Sell
FROM            Items INNER JOIN
                         Sell_items ON Items.Id_ItemS = Sell_items.Id_items
WHERE        (Items.Id_ItemS = 1)
 UNION ALL
SELECT        Items.Id_ItemS, Items.Name_ar, Items.Number_Id, 1 AS RecursionLevel, CAST(Hierarchy + ':' + CAST(Items.Id_ItemS AS varchar(100)) AS varchar(100)) AS Hierarchy, Sell_items.Id_Sell
FROM            Recursive_CTE AS parent INNER JOIN
                         Items ON parent.Id_items = Items.Number_Id INNER JOIN
                         Sell_items ON Items.Id_ItemS = Sell_items.Id_items )
SELECT * FROM Recursive_CTE ORDER BY Hierarchy

但结果为空

我想修改查询？

期望的结果 enter image description here

Answer 1

我将其视为数据问题。您没有任何记录可以满足您的查询。

在两张桌子上进行内部联接后，我看不到任何items.Id_ItemS = 1 - Items, Sell_items

  SELECT 
       Items.Id_ItemS, 
       Items.Name_ar, 
       Items.Number_Id, 
       1 AS RecursionLevel, 
       CAST(Items.Id_ItemS AS varchar(100)) AS Hierarchy,
       Sell_items.Id_Sell 
  FROM  Items INNER JOIN Sell_items ON Items.Id_ItemS = Sell_items.Id_items
       WHERE (Items.Id_ItemS = 1)

如果删除where条件（Items.Id_ItemS = 1），您将获得结果。

希望这能帮到你！

Answer 2

将以下3个插入添加到Sell_items，您将获得结果......

INSERT dbo.Sell_items (Id_Sell, Id_items, price) VALUES (5, 1, 270000.0000);
INSERT dbo.Sell_items (Id_Sell, Id_items, price) VALUES (6, 3, 280000.0000);
INSERT dbo.Sell_items (Id_Sell, Id_items, price) VALUES (7, 4, 290000.0000);

另请注意，您并未将RecursionLevel列归罪。您需要将1添加到上一个值...

parent.RecursionLevel + 1 AS RecursionLevel,

Answer 3

我来回答这个问题，非常好

WITH Recursive_CTE (Id_ItemS,Name_ar,Number_Id,RecursionLevel,Hierarchy) AS (
SELECT        Items.Id_ItemS, Items.Name_ar, Items.Number_Id, 1 AS RecursionLevel, CAST(Items.Id_ItemS AS varchar(100)) AS Hierarchy
FROM            Items
where (Id_ItemS=1)
 UNION ALL
SELECT        Items.Id_ItemS, Items.Name_ar, Items.Number_Id, RecursionLevel+1 AS RecursionLevel, CAST(Hierarchy + ':' + CAST(Items.Id_ItemS AS varchar(100)) AS varchar(100)) AS Hierarchyss
FROM            Recursive_CTE AS parent INNER JOIN
                         Items ON parent.Id_items = Items.Number_Id)
SELECT        Id_ItemS, Name_ar, Number_Id, RecursionLevel, Hierarchy, Sell_items.Id_Sell, Sell_items.price, Sell_items.Id_items2
FROM           Recursive_CTE  INNER JOIN
                      Sell_items    ON Sell_items.Id_items2 = Recursive_CTE.Id_items
ORDER BY Hierarchy

结果

Id_ItemS    Name_ar Number_Id   RecursionLevel  Hierarchy   Id_Sell price   Id_items2
6   2015    5   4   1:3:5:6 3   20000.00    6
7   2016    5   4   1:3:5:7 4   270000.00   7
7   2016    5   4   1:3:5:7 5   998877.00   7

从两个表CAST查询

3 个答案:

结果