Question

我需要一些帮助。

我希望在任何账单中完全具有相同ID的材料数量。

像这样

bill no. 001
jellopy x1ea
jellopy x1ea
jellopy x1ea
zargon x1ea

结果应该是

bill no. 001
jellopy x3ea
zargon x1ea

所以，我想做这样的事情

1.select + sum 2.update 3.delete duplicate

这是我的旧（dbill）表

dbill

id  mat  qty
01  A1   1
01  A1   1
01  A1   1
01  A2   1

id  mat  qty
[01  A1   1] < same mat&id = SUM it
[01  A1   1] < same mat&id = SUM it
[01  A1   1] < same mat&id = SUM it
 01  A2   1

这是SQLFiddle for test http://sqlfiddle.com/#!15/b30a3c

1使用相同材料的SUM数量

SELECT mat,id,sum(qty) result
FROM dbill
GROUP BY id,mat

[2]得到了这样的结果

id  mat  qty
01  A1   3
01  A2   1

[3]所以......我会像这样更新

UPDATE dbill
SET qty = result
FROM dbill t
INNER JOIN
(SELECT mat,id,sum(qty) result
FROM dbill
GROUP BY id,mat) s
ON s.id = t.id
AND s.mat = t.mat

问题是当我[3] UPDATE这里是结果

id  mat  qty
01  A1   3
01  A1   3
01  A1   3
01  A2   3

因为正确的结果应该是

id  mat  qty
01  A1   3
01  A1   3
01  A1   3
01  A2   1     <

非常感谢您的理解和回答......

Answer 1

对我来说，您的查询似乎没问题，只需将UPDATE dbill替换为UPDATE t

即可

UPDATE t <----
SET qty = result
FROM dbill t
INNER JOIN
(SELECT mat,id,sum(qty) result
 FROM dbill
 GROUP BY id,mat) s
ON s.id = t.id
AND s.mat = t.mat

Answer 2

这可能不太优雅但应该有效

  UPDATE dbill t
  SET t.qty = (select sum(qty) from dbill t2 where t2.id=t.id and t2.mat=t.mat)

Answer 3

问题解决了!!!

在这里，这是我的解决方案。（我可以从我的应用程序获得t3.id，所以我只是连接它。）

UPDATE dbill t3
SET qty = t2.result
FROM (
SELECT matno,hbill_ids,sum(qty) result
FROM dbill t1
GROUP BY hbill_ids,matno) t2
WHERE ( t3.hbill_ids = t2.hbill_ids
AND t3.matno = t2.matno )
AND ( t3.id = 372
OR t3.id = 373
OR t3.id = 374
OR t3.id = 375 );
DELETE FROM dbill t3
WHERE id IN ( SELECT id
FROM dbill y1
WHERE EXISTS ( 
SELECT *
FROM dbill y2
WHERE y1.matno = y2.matno
AND y1.qty = y2.qty
AND y1.hbill_ids = y2.hbill_ids
AND y1.id < y2.id
AND ( t3.id = 372
OR t3.id = 373
OR t3.id = 374
OR t3.id = 375 )
));

SQL SELECT WHERE中的多个更新记录

3 个答案: