Question

我正在尝试重写SQL Server 2008的Oracle查询：

UPDATE "LOAD"."UNITS_OF_MEASURE" 
SET ("UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE", "UOM_REFERENCE", "UOM_SUBTYPE_ID") =
                 ( SELECT "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE", 0 AS "UOM_REFERENCE", NULL AS "UOM_SUBTYPE_ID"
                    FROM ( SELECT DISTINCT "UOM_TYPE_ID", "UOM_CODE", "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE"
                            FROM "LOAD"."LOADER_UNITS_OF_MEASURE"
                            INNER JOIN "LOAD"."UOM_TYPES" ON ("UOM_TYPES"."UOM_TYPE_CODE"="LOADER_UNITS_OF_MEASURE"."UOM_TYPE_CODE")
                         ) SELECTION
                    WHERE ("SELECTION"."UOM_TYPE_ID"="UNITS_OF_MEASURE"."UOM_TYPE_ID")
                    AND ("SELECTION"."UOM_CODE"="UNITS_OF_MEASURE"."UOM_CODE")
                )
WHERE EXISTS  ( SELECT "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE", 0 AS "UOM_REFERENCE", NULL AS "UOM_SUBTYPE_ID"
                  FROM ( SELECT DISTINCT "UOM_TYPE_ID", "UOM_CODE", "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE"
                          FROM "LOAD"."LOADER_UNITS_OF_MEASURE"
                          INNER JOIN "LOAD"."UOM_TYPES" ON ("UOM_TYPES"."UOM_TYPE_CODE"="LOADER_UNITS_OF_MEASURE"."UOM_TYPE_CODE")
                        ) SELECTION
                 WHERE ("SELECTION"."UOM_TYPE_ID"="UNITS_OF_MEASURE"."UOM_TYPE_ID")
                 AND ("SELECTION"."UOM_CODE"="UNITS_OF_MEASURE"."UOM_CODE")
)

内部SELECT查询应该保持不变，因为查询是由DBMS独立的查询构建器层自动组成的。

我尝试了以下语法：

UPDATE "LOAD"."UNITS_OF_MEASURE" 
SET "UOM_DESC" = i."UOM_DESC", "UOM_SYMBOL" = i."UOM_SYMBOL", "UOM_MUL_FACTOR" = i."UOM_MUL_FACTOR", "UOM_ADD_FACTOR" = i."UOM_ADD_FACTOR", "UOM_DEC_PLACE" = i."UOM_DEC_PLACE",
     "UOM_REFERENCE" = 0, "UOM_SUBTYPE_ID" = NULL FROM
                 ( SELECT "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE", 0 AS "UOM_REFERENCE", NULL AS "UOM_SUBTYPE_ID"
                    FROM ( SELECT DISTINCT "UOM_TYPE_ID", "UOM_CODE", "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE"
                            FROM "LOAD"."LOADER_UNITS_OF_MEASURE"
                            INNER JOIN "LOAD"."UOM_TYPES" ON ("UOM_TYPES"."UOM_TYPE_CODE"="LOADER_UNITS_OF_MEASURE"."UOM_TYPE_CODE")
                         ) SELECTION
                    WHERE ("SELECTION"."UOM_TYPE_ID"="UNITS_OF_MEASURE"."UOM_TYPE_ID")
                    AND ("SELECTION"."UOM_CODE"="UNITS_OF_MEASURE"."UOM_CODE")
                )i
WHERE EXISTS ( SELECT "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE", 0 AS "UOM_REFERENCE", NULL AS "UOM_SUBTYPE_ID"
                  FROM ( SELECT DISTINCT "UOM_TYPE_ID", "UOM_CODE", "UOM_DESC", "UOM_SYMBOL", "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE"
                          FROM "LOAD"."LOADER_UNITS_OF_MEASURE"
                          INNER JOIN "LOAD"."UOM_TYPES" ON ("UOM_TYPES"."UOM_TYPE_CODE"="LOADER_UNITS_OF_MEASURE"."UOM_TYPE_CODE")
                        ) SELECTION
                 WHERE ("SELECTION"."UOM_TYPE_ID"="UNITS_OF_MEASURE"."UOM_TYPE_ID")
                 AND ("SELECTION"."UOM_CODE"="UNITS_OF_MEASURE"."UOM_CODE")
)

但遗憾的是，第9-10行的"UNITS_OF_MEASURE"."UOM_TYPE_ID"和"UNITS_OF_MEASURE"."UOM_CODE"无法解析。

Answer 1

基本上，这看起来好像是将派生表与外部表（UPDATE的目标）相关联，而不是将其连接到后者。这在Transact-SQL中不起作用（我也怀疑这是否适用于Oracle，事实上）。

但是，您可以使用UPDATE...FROM语法：只需删除中间层SELECT并使用最内层的SELECT作为派生表加入UNITS_OF_MEASURE，即如下所示：< / p>

UPDATE "LOAD"."UNITS_OF_MEASURE" 
SET "UOM_DESC" = "SELECTION"."UOM_DESC",
    "UOM_SYMBOL" = "SELECTION"."UOM_SYMBOL",
    "UOM_MUL_FACTOR" = "SELECTION"."UOM_MUL_FACTOR",
    "UOM_ADD_FACTOR" = "SELECTION"."UOM_ADD_FACTOR",
    "UOM_DEC_PLACE" = "SELECTION"."UOM_DEC_PLACE",
    "UOM_REFERENCE" = 0,
    "UOM_SUBTYPE_ID" = NULL
FROM ( SELECT DISTINCT "UOM_TYPE_ID", "UOM_CODE", "UOM_DESC", "UOM_SYMBOL",
                       "UOM_MUL_FACTOR", "UOM_ADD_FACTOR", "UOM_DEC_PLACE"
       FROM "LOAD"."LOADER_UNITS_OF_MEASURE"
       INNER JOIN "LOAD"."UOM_TYPES" ON ("UOM_TYPES"."UOM_TYPE_CODE"="LOADER_UNITS_OF_MEASURE"."UOM_TYPE_CODE")
     ) SELECTION
WHERE ("SELECTION"."UOM_TYPE_ID"="UNITS_OF_MEASURE"."UOM_TYPE_ID")
  AND ("SELECTION"."UOM_CODE"="UNITS_OF_MEASURE"."UOM_CODE")
;

这会将SELECTION派生表加入"LOAD"."UNITS_OF_MEASURE"并使用派生表的数据来更新其他表的列。

选择SQL Server 2008中存在的多个更新

1 个答案: