Question

练习它返回给定的字符串而不需要任何元音，例如＆＃34;车＆＃34;会回来＆＃34; cr＆＃34;。

def anti_vowel(text):
    #returns text without vowels
    answer = ""
    i = 0
    while i <= len(text) -1:
        for text[i] in "aeiouAEIOU" = False:
            answer += text[i]
            i += 1   
    answer = answer.join(text)

    return answer

Answer 1

问题出在这一行：

for text[i] in "aeiouAEIOU" = False:

=用于分配，用以下内容替换整行：

for text[i] not in "aeiouAEIOU":

你也有缩进问题，你的整个功能应该是这样的：

def anti_vowel(text):
    #returns text without vowels
    answer = ""
    i = 0
    while i <= len(text) -1:
        for text[i] not in "aeiouAEIOU":
            answer += text[i]
        i += 1   
    answer = answer.join(text)

    return answer

这将是Pythonic版本：

def anti_vowel(text):
    return ''.join(c for c in text if c.lower() not in "aeiou")

在本练习中我从字符串中删除元音有什么问题？

1 个答案: