Question

我不是很喜欢数据库，我对实施本教程有以下疑问：https://mariadb.org/jquery-and-gis-distance-in-mariadb/

所以基本上我的疑问与这个SQL语句有关，它创建了一个函数来计算MariaDB数据库上两个 point 之间的距离：

CREATE FUNCTION earth_circle_distance(point1 point, point2 point) RETURNS double
    DETERMINISTIC
begin
  declare lon1, lon2 double;
  declare lat1, lat2 double;
  declare td double;
  declare d_lat double;
  declare d_lon double;
  declare a, c, R double;

  set lon1 = X(GeomFromText(AsText(point1)));
  set lon2 = X(GeomFromText(AsText(point2)));
  set lat1 = Y(GeomFromText(AsText(point1)));
  set lat2 = Y(GeomFromText(AsText(point2)));

  set d_lat = radians(lat2 - lat1);
  set d_lon = radians(lon2 - lon1);

  set lat1 = radians(lat1);
  set lat2 = radians(lat2);

  set R = 6372.8; -- in kilometers

  set a = sin(d_lat / 2.0) * sin(d_lat / 2.0) + sin(d_lon / 2.0) * sin(d_lon / 2.0) * cos(lat1) * cos(lat2);
  set c = 2 * asin(sqrt(a));

  return R * c;
end

我的问题是执行上一个语句我收到以下错误消息：

Error
----------------------------------------------------
Static analysis:

2 errors were found during analysis.
    1. Unrecognized data type. (near "point" at position 45)
    2. Unrecognized data type. (near "point" at position 59)

SQL query:

CREATE FUNCTION earth_circle_distance(point1 point, point2 point) RETURNS double DETERMINISTIC begin declare lon1, lon2 double 

MySQL said: 

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 4

PhpMyAdmin 使用2个红色标记在上一个参数的第一行上标记点数据类型：

CREATE FUNCTION earth_circle_distance(point1 point, point2 point) RETURNS double

但我不认为这可能是真正的问题（我认为这可能是 PhpMyAdmin 不知道），因为它也标记为红色此cration查询：

CREATE TABLE gis_point  (g POINT);

但它工作正常，没有错误，并正确创建表。

那么，这是错的？可以依赖 PhpMyAdmin 或者我错过了什么？应该存储此功能的位置？

Answer 1

更改分隔符。否则，函数定义将在第一个sum处结束，这将使其不完整。

当我尝试在MariaDB数据库上创建此函数（使用点数据类型）时，为什么会出现此错误？

1 个答案: