Question

我想按字母顺序对单个对象进行排序......

保持其关键和价值ex：

输入是： {2：＆＃34; a＆＃34;，3：＆＃34; e＆＃34;，4：＆＃34; h＆＃34;，5：＆＃34; g＆＃34;，6：＆＃34; d＆＃34;，7：＆＃34;我＆＃34;，8：＆＃34; c＆＃34;，9：＆＃34; f＆＃34 ;，10：＆＃34; b＆＃34;}

我需要输出： {2：＆＃34; a＆＃34;，10：＆＃34; b＆＃34;，8：＆＃34; c＆＃34;，6：＆＃34; d＆＃34;，3：＆＃34; e＆＃34;，9：＆＃34; f＆＃34;，5：＆＃34; g＆＃34;，4：＆＃34; h＆＃ 34;，7：＆＃34;我＆＃34;}

这是我的js代码：

var myObject = {2: "a", 3: "e", 4: "h", 5: "g", 6: "d", 7: "i", 8: "c", 9: "f", 10: "b"}

keysSorted = Object.keys(myObject).sort(function(a,b){return myObject[a]-myObject[b]});
console.log(keysSorted);

这是我的小提琴： https://jsfiddle.net/j7yujL2y/

Answer 1

如果您只想对属性名称数组进行排序，请使用String#localeCompare来比较字符串。

var myObject = {
  2: "a",
  3: "e",
  4: "h",
  5: "g",
  6: "d",
  7: "i",
  8: "c",
  9: "f",
  10: "b"
}

keysSorted = Object.keys(myObject).sort(function(a, b) {
  return myObject[a].localeCompare(myObject[b])
});
console.log(keysSorted);

Answer 2

奇怪的要求。

你的意思是你需要console.log（）的输出看起来像你写的那样？（我认为这是不可能的。：D）

为了完成这项特定的工作，尝试使用alpha作为键创建一个新地图，将数字作为值，尽管它看起来不像你想要的那样

Answer 3

对象是无序地图，因此您无法对其进行排序但是，您可以单独获取已排序的键和值它将是这样的：

＆＃13;

let myObject = {2: "Australia", 3: "China", 4: "Japan", 5: "Thailand", 6: "India", 7: "Malaysia", 8: "South Korea", 9: "Hong Kong", 10: "Taiwan", 11: "Philippines", 12: "Vietnam", 13: "France", 14: "United Kingdom", 15: "Germany", 16: "Sweden", 17: "Italy", 18: "Greece", 19: "Spain", 20: "Austria", 21: "The Netherlands", 22: "Belgium", 23: "Switzerland", 24: "United Arab Emirates", 26: "Ukraine", 27: "Russian Federation", 29: "Portugal", 30: "Saudi Arabia", 31: "Denmark", 33: "Norway", 34: "United States", 35: "Canada", 36: "Mexico", 38: "Poland", 39: "Czech Republic", 40: "Ireland", 41: "Bulgaria", 42: "Finland", 43: "Slovenia", 44: "Romania"}

let values = Object.keys(myObject).map(k => myObject[k]).sort();
let keys = Object.keys(myObject)
	.sort((a, b) => values.indexOf(myObject[a]) - values.indexOf(myObject[b]));

console.log(values, keys);

＆＃13;

Answer 4

您可以按特定顺序创建Array或Map个对象

var myObject = {
  2: "a",
  3: "e",
  4: "h",
  5: "g",
  6: "d",
  7: "i",
  8: "c",
  9: "f",
  10: "b"
};
const keys = Array.from({
  length: Object.keys(myObject).length
});
let order = "abcdefghijklmnopqrstuvwxyz";
let arr = [];
const map = new Map();
for (let key in myObject) {
  arr[order.indexOf(myObject[key])] = {
    [key]: myObject[key]
  };
}
for (let prop of arr) {
  map.set(prop[Object.keys(prop)], prop)
}
for (let prop of map) {
  console.log(prop)
}
console.log(arr);

Answer 5

你可以尝试这个：

var keysSorted = Object.keys(myObject).sort(function (a, b) {
    return myObject[a].localeCompare(myObject[b])
});
var SortedList = [];
keysSorted.forEach(function (value) {
    SortedList.push(myObject[value]);
});

Answer 6

 const myObject = {
  2: "a",
  3: "e",
  4: "h",
  5: "g",
  6: "d",
  7: "i",
  8: "c",
  9: "f",
  10: "b"
}

const keysSorted = Object.keys(myObject).sort(function(a, b) {
      return myObject[a].localeCompare(myObject[b])
    });
    console.log(keysSorted);

const sortedObj={};
keysSorted.forEach(key)={
//convert key to string because in JS,Object which has keys as number type are automatically sorted in ascending//
sortedObj[' '+key] = myObject[key];
})
console.log(sortedObj);

如何按字母顺序排序单个对象？

6 个答案: