我有一张包含以下数据的表
Item
......
xzypq
abdcfe
如何对列中的字符串进行排序并获得以下结果?
Item
......
pqxyz
abcdef
答案 0 :(得分:2)
可以尝试以下链接,这可能有助于http://social.technet.microsoft.com/wiki/contents/articles/19492.sort-letters-in-a-phrase-using-t-sql.aspx
/*Create sample table*/
IF OBJECT_ID('tempdb..#Text', 'U') IS NOT NULL
DROP TABLE #Test;
CREATE TABLE #Test
(
ID INT IDENTITY(1, 1) ,
Phrase VARCHAR(255)
);
/*Populate the table with sample data*/
INSERT #Test
( Phrase )
VALUES
( 'CHICAGO' ),
( 'NEW YORK' ),
( 'HOUSTON' ),
( 'SAN FRANCISCO' );
/*This is the final solution*/;
WITH base
AS ( SELECT L.[char] ,
T.ID ,
T.Phrase
FROM #Test T
CROSS APPLY ( SELECT SUBSTRING(T.Phrase, 1 + Number, 1) [char]
FROM master..spt_values
WHERE Number < DATALENGTH(T.Phrase)
AND type = 'P'
) L
)
SELECT DISTINCT
b1.Phrase ,
REPLACE(( SELECT '' + [char]
FROM base b2
WHERE b1.Phrase = b2.Phrase
ORDER BY [char]
FOR
XML PATH('')
), ' ', ' ') AS columns2
FROM base AS b1;
答案 1 :(得分:0)
使用Recursive CTE
也可以这样做。
SELECT 'xzypq' NAME
INTO #temp
UNION ALL
SELECT 'abdcfe'
;WITH cte
AS (SELECT Cast(NAME AS VARCHAR(50)) AS st,NAME AS name1,1 AS rn
FROM #temp
UNION ALL
SELECT Cast(Substring(NAME, rn, 1) AS VARCHAR(50)),name1,rn + 1
FROM cte a
JOIN #temp b
ON a.name1 = b.NAME
AND rn < Len(a.name1) + 1)
SELECT DISTINCT (SELECT '' + st
FROM cte b
WHERE a.name1 = b.name1
AND rn <> 1
ORDER BY st
FOR XML PATH ('')) AS Ordered_String
FROM cte a
WHERE rn <> 1
<强>结果强>
Ordered_String
--------------
abcdef
pqxyz