Question

嘿，我的SQL查询有问题。让我们拿这个例子数据

itemID  catID  attrib1  attrib2
  1       1       10       5   
  2       1       10       7
  3       1        5      10
  4       2       18      15

我想为每个类别返回最佳项目（attrib1优先于attrib2）

显然，“SELECT catID，MAX（attrib1），MAX（attrib2）FROM test_table GROUP BY catID”不起作用，因为它将返回10＆amp;第一只猫10只。

那么无论如何要告诉MySQL从attrib2行中选择最大值但是只考虑attrib1也是最大值的那些？即返回以下数据

 catID  attrib1  attrib2
   1       10       7   
   2       18      15

Answer 1

您可以获得最佳的attrib1值，然后加入attrib2值并获得每个attrib1值的最佳值：

select t2.catID, t2.attrib1, max(t2.attrib2)
from
(
  select catID, max(attrib1) as attrib1
  from test_table
  group by catID
) t1
inner join test_table t2 on t2.catID = t1.catID and t2.attrib1 = t1.attrib1
group by t2.catID, t2.attrib1

Answer 2

SELECT tt.catId, tt.attrib1, MAX(tt.attrib2)
FROM   test_table tt
GROUP BY tt.catID, tt.attrib1
WHERE  tt.attrib1 = (SELECT MAX(t2.attrib1) FROM test_table t2 WHERE t2.catID = tt.catID)

Answer 3

使用：

SELECT x.catid,
       x.max_attrib1 AS attrib1,
       (SELECT MAX(attrib2)
          FROM YOUR_TABLE y
         WHERE y.catid = x.catid
           AND y.attrib1 = x.max_attrib1) AS attrib2
  FROM (SELECT t.catid,
               MAX(t.attrib1) AS max_attrib1
          FROM YOUR_TABLE t
      GROUP BY t.catid) x

Answer 4

SELECT catID, max1, max2 FROM
((SELECT Max(attrib1) as max1, catID GROUP BY attrib1) as t1
INNER JOIN
(SELECT MAX(attrib2) as max2, catID GROUP BY attrib2) as t2
ON t1.catID = t2.catID) as t3

SQL：在多列上使用GROUP BY和MAX

4 个答案: