Question

当前表事件：

|  eventId  |  personId  |  type  | title   |  score  |
+-----------+------------+--------+---------+---------+
| 1         | 1          | movie  | Mission | 12      |
| 2         | 1          | movie  | UNCLE   | 32      |
| 3         | 1          | show   | U2      | 17      |
| 4         | 1          | show   | Leroy   | 13      |
| 5         | 2          | movie  | Holmes  | 19      |
| 6         | 2          | movie  | Compton | 14      |
| 7         | 2          | show   | Imagine | 22      |
| 8         | 2          | show   | Kane    | 22      |

MySQL示例：

SELECT @personId:=personId as personId,
(
  SELECT title FROM Events 
  WHERE rate = (SELECT MAX(score) FROM Events) 
  AND type = ‘movie’ AND personId=@personId
) as movie,
(
  SELECT title FROM Events 
  WHERE rate = (SELECT MAX(score) FROM Events) 
  AND type = ‘movie’ AND personId=@personId
) as show,
FROM Events
GROUP BY personId
ORDER BY personId;

期望的输出：

|  personId  |  movie   |  show   |
+------------+----------+---------+
| 1          | UNCLE    | U2      |
| 2          | Holmes   | Imagine |

所需的结果是在“事件”表中显示电影的MAX（）分数和每人的显示。我的实际输出包含NULLS并需要很长时间才能加载。我的实际事件表有大约20,000个条目。

UPDATE解决方案（从前两个答案派生以提高性能）

SELECT e.personId,
(
  SELECT o.title 
  FROM Events o
  LEFT JOIN Events b 
      ON o.personId = b.personId AND o.score < b.score
      AND o.type = b.type
  WHERE o.type = 'movie' AND o.personId=e.personId  LIMIT 1
) as best_movie ,
(
  SELECT o.title
  FROM Events o
  LEFT JOIN Events b 
      ON o.personId = b.personId AND o.score < b.score
      AND o.type = b.type
  WHERE o.type = 'show' AND o.personId=e.personId  LIMIT 1
) as best_show
FROM Events e
GROUP BY e.personId
ORDER BY e.personId

Answer 1

我不确定这是否正是你所需要的。

但我只是猜测，可能你不需要多列？

http://sqlfiddle.com/#!9/04b27/4

SELECT e.* 
FROM `events` e
left join `events` e1
on e.type = e1.type
and e.score<e1.score
WHERE e1.eventId IS NULL
GROUP BY personId, type, score

更新如果您需要每人最高分数+类型，您可以

http://sqlfiddle.com/#!9/04b27/13

SELECT e.* 
FROM `events` e
left join `events` e1
on e.personId = e1.personId
and e.type = e1.type
and e.score<e1.score
WHERE e1.eventId IS NULL
GROUP BY personId,  score

基于Max（）的SELECT和GROUP BY多列

1 个答案: