Question

我正在使用JavaFX构建绘图程序。我试图使用GraphicsContext绘制一个Rectangle并设法让它在画布上绘制。但是，无论我在哪里点击，它总是从原点开始。当我松开鼠标时（这已经正确完成），矩形停止被绘制，但是当我按下鼠标时，它不会被绘制。这是我的代码：

public RectController(Canvas c, Scene s, BorderPane borderPane){
    this.borderPane = borderPane;
    this.scene = scene;
    this.graphicsContext = canvas.getGraphicsContext2D();

    rectangle = new Rectangle();
    rectangle.setStrokeWidth(1.0);
    rectangle.setManaged(true);
    rectangle.setMouseTransparent(true);

    //when you first press down on the mouse
    pressMouse = event -> {
     //   borderPane.getChildren().add(rectangle); --> REMOVED
        double startX = event.getX();
        double startY = event.getY();
    };

    releaseMouse = event -> {
        borderPane.getChildren().remove(rectangle);
        double width  = Math.abs(event.getX() - startX);
        double height = Math.abs(event.getY() - startY);
        graphicsContext.strokeRect(startX, startY, width, height);
        borderPane.setOnMousePressed(null);
        borderPane.setOnMouseDragged(null);
        borderPane.setOnMouseReleased(null);
    };

    dragMouse = event -> {
        rectangle.setWidth(event.getX());
        rectangle.setHeight(event.getY());
    };

}

非常感谢任何帮助。

Answer 1

这接近你的要求吗？

@FXML AnchorPane apMain;

Rectangle rectangle;

@Override
public void initialize(URL url, ResourceBundle rb) {

}

@FXML void handleOnMouseClick(MouseEvent event)
{
    double x = event.getSceneX();
    double y = event.getSceneY();

    rectangle = new Rectangle();
    rectangle.setX(x);
    rectangle.setY(y);
    rectangle.setWidth(25);
    rectangle.setHeight(25);
    apMain.getChildren().add(rectangle);

}

@FXML void handleOnMouseDrag(MouseEvent event)
{

    rectangle.setWidth(event.getSceneX() - x);
    rectangle.setHeight(event.getSceneY() - y);
}

@FXML void handleOnMouseRelease(MouseEvent event)
{
    apMain.getChildren().remove(rectangle);
}

你需要做这件事。这是原油。

如何将JavaFX上绘制的矩形的原点更改为单击鼠标的位置？

1 个答案: