Question

所以我开始在我的应用程序中设置不同功能的键，我想知道有没有办法设置鼠标右键/左键做什么？我无法在KeyCode.java中找到任何鼠标事件而且我不确定如何申请。

这是我的代码：

public class Exercise_31 extends Application {

    @Override
    public void start(Stage primaryStage) throws Exception {

        PendulumPane pendulumPane = new PendulumPane(500, 500);

        Scene scene = new Scene(pendulumPane);
        primaryStage.setTitle("Pendulum Animation");
        primaryStage.setScene(scene);
        pendulumPane.play();
        primaryStage.show();


        scene.setOnKeyPressed(e-> {
            switch (e.getCode()) {
                case UP: pendulumPane.increase(); break;
                case DOWN: pendulumPane.decrease(); break;
                case LEFTMOUSECLICK?  
            }
        });


    }

    public static void main(String[] args) {
        Application.launch(args);
    }

    private class PendulumPane extends Pane {

        private double w = 400;
        private double h;
        PathTransition bPath;

        Circle topC;
        Circle lowerC;
        Line line;
        Arc arc;

        PendulumPane(double width, double height) {

            w = width;
            h = height;
            setPrefWidth(w);
            setPrefHeight(h);
            arc = new Arc(w / 2, h * 0.8, w * 0.15, w * 0.15, 180, 180);
            arc.setFill(Color.TRANSPARENT);
            arc.setStroke(Color.BLACK);

            lowerC = new Circle(arc.getCenterX() - arc.getRadiusX(), arc.getCenterY(), 10);
            topC = new Circle(arc.getCenterX(), arc.getCenterY() - h / 2, lowerC.getRadius() / 2);
            arc = new Arc(topC.getCenterX(), topC.getCenterY(), w / 2, h / 2, 240, 60);
            line = new Line(
                    topC.getCenterX(), topC.getCenterY(),
                    lowerC.getCenterX(), lowerC.getCenterY());

            line.endXProperty().bind(lowerC.translateXProperty().add(lowerC.getCenterX()));
            line.endYProperty().bind(lowerC.translateYProperty().add(lowerC.getCenterY()));
            bPath = new PathTransition();
            bPath.setDuration(Duration.millis(4000));
            bPath.setPath(arc);
            bPath.setNode(lowerC);
            bPath.setOrientation(PathTransition.OrientationType.NONE);
            bPath.setCycleCount(PathTransition.INDEFINITE);
            bPath.setAutoReverse(true);

            getChildren().addAll(lowerC, topC,line);

        }

        public void play() {
            bPath.play();
        }


        public void increase() {
            bPath.setRate(bPath.getCurrentRate() + 1);
        }

        public void decrease() {
            bPath.setRate(bPath.getCurrentRate() - 1);
        }

        public void stop() {
            bPath.setRate(bPath.getCurrentRate() * 0);
        }

        public void start() {
            bPath.setRate(bPath.getCurrentRate() + 1);
        }
    }
}

我要做的是右键单击鼠标按钮停止移动并左键单击再次启动它。我该怎么办？谢谢。

Answer 1

您的活动是KeyEvent。如果您为鼠标定义了一个监听器（例如setOnMouseReleased，则会得到一个MouseEvent，并且在该监听器上您可以检查是否按下某些键，这些键通常与鼠标单击结合使用：

event.isAltDown();
event.isControlDown();
event.isMetaDown();

如果您需要更多东西，您必须自己实施。请参阅JavaDoc以了解MouseEvent。

如何在JavaFX中检测鼠标单击？

1 个答案: