Question

我有一个主要的PHP类，如：

Application.EnableEvents = False

有一种方法，存储在class MyClass { public $a; public $b; function __construct() { $this->a = new \SomeClass(); $this->b = 'some string'; } }（$a）属性中的类可以访问SomeClass值，该值实际上是存储在启动{的类中的属性{1}}（$b）？

Answer 1

你可以这样做：

class MyClass {
    public $a;
    public $b;

    function __construct()
    {
      $this->a = new \SomeClass($this);
      $this->b = 'some string';
    }
}

class SomeClass {
    public $mc;

    function __construct(MyClass $mc)
    {
      $this->mc = $mc;
    }
}

$myClass = new MyClass();
echo $myClass->a->mc->b;

输出结果为：some string

Answer 2

您可以这样做：

class MyClass {
    public $a;
    public $b;

    function __construct()
    {
       $this->b = 'some string';
       $this->a = new \SomeClass($this->b);
    }
}   

class SomeClass{

    function __construct($b) 
    {
        echo $b; // it will become a $this->b as given while creating new class in MyClass
    }
}

具有属性的PHP类，这些对象可以访问这些对象

2 个答案: