Question

我想在python中使用来自文本文件的单词而不是直接写入python文件的单词（在这种情况下代码完美地工作）。但是当我想要导入它们时，我会得到这个列表：

[['amazement', ' awe', ' bombshell', ' curiosity', ' incredulity', '\r\n'], ['godsend', ' marvel', ' portent', ' prodigy', ' revelation', '\r\n'], ['stupefaction', ' unforeseen', ' wonder', ' shock', ' rarity', '\r\n'], ['miracle', ' abruptness', ' astonishment\r\n']]

我希望将单词排序在一个列表中，例如：

["amazement", "awe", "bombshell"...]

这是我的python代码：

import random

#Welcome the player
print("""
    Welcome to Word Jumble.
        Unscramble the letters to make a word.
""")


filename = "words/amazement_words.txt"

lst = []
with open(filename) as afile:
    for i in afile:
        i=i.split(",")
        lst.append(i)
print(lst)

word = random.choice(lst)
theWord = word

jumble = ""
while(len(word)>0):
    position = random.randrange(len(word))
    jumble+=word[position]
    word=word[:position]+word[position+1:]
print("The jumble word is: {}".format(jumble))

#Getting player's guess
guess = input("Enter your guess: ")

#congratulate the player
if(guess==theWord):
    print("Congratulations! You guessed it")
else:
    print ("Sorry, wrong guess.")

input("Thanks for playing. Press the enter key to exit.")

我有一个带文字的文字文件：

    amazement, awe, bombshell, curiosity, incredulity,
    godsend, marvel, portent, prodigy, revelation,
    stupefaction, unforeseen, wonder, shock, rarity,
    miracle, abruptness, astonishment

感谢您的帮助和任何建议！

Answer 1

准单行做到了：

with open("list_of_words.txt") as f:
    the_list = sorted(word.strip(",") for line in f for word in line.split())

print(the_list)

在gen-comprehension中使用双for
分裂空格是一个诀窍：它摆脱了行终止字符和多个空格。然后，使用strip()删除逗号。
在生成的生成器理解

sorted

结果：

['abruptness', 'amazement', 'astonishment', 'awe', 'bombshell', 'curiosity', 'godsend', 'incredulity', 'marvel', 'miracle', 'portent', 'prodigy', 'rarity', 'revelation', 'shock', 'stupefaction', 'unforeseen', 'wonder']

这种快速方法的唯一缺点是如果2个单词只用逗号分隔，它将按原样发出2个单词。

在后一种情况下，只需在gencomp中添加for，以便根据逗号执行拆分并删除空结果字符串（if word）：

with open("list_of_words.txt") as f:
    the_list = sorted(word for line in f for word_commas in line.split() for word in word_commas.split(",") if word)

print(the_list)

或者在后一种情况下，可能使用正则表达式拆分更好（我们也需要丢弃空字符串）。拆分表达式为空白或逗号。

import re

with open("list_of_words.txt") as f:
    the_list = sorted(word for line in f for word in re.split(r"\s+|,",line) if word)

Answer 2

请尝试以下代码：

import random

#Welcome the player
print("""
    Welcome to Word Jumble.
        Unscramble the letters to make a word.
""")

name = "   My name   "

filename = "words/amazement_words.txt"

lst = []
file = open(filename, 'r')
data = file.readlines()

another_lst = []
for line in data:
    lst.append(line.strip().split(','))
print(lst)
for line in lst:
    for li in line:
        another_lst.append(li.strip())

print()
print()
print(another_lst)

word = random.choice(lst)
theWord = word

jumble = ""
while(len(word)>0):
    position = random.randrange(len(word))
    jumble+=word[position]
    word=word[:position]+word[position+1:]
print("The jumble word is: {}".format(jumble))

#Getting player's guess
guess = input("Enter your guess: ")

#congratulate the player
if(guess==theWord):
    print("Congratulations! You guessed it")
else:
    print ("Sorry, wrong guess.")

input("Thanks for playing. Press the enter key to exit.")

Answer 3

str.split（）会生成一个列表，因此如果将其附加到结果中，则会获得一个列表列表。解决方案是连接2列表（+）

你可以摆脱＆＃39; \ r \ n＆＃39;在拆分之前剥离我

Answer 4

使用

lst.extend(i)

而不是

lst.append(i)

split返回一个列表，每次都会列出一个列表。使用extend代替将解决您的问题。

使用Python中的读取文本文件创建一个包含字符串的列表

4 个答案: