嗨我有这样的表，它有一对一的关系
report_sites
id | date
1 | 2016-11-02 10:00:00
2 | 2016-11-02 11:00:00
3 | 2016-11-02 12:00:00
4 | 2016-11-03 17:00:00
5 | 2016-11-03 16:00:00
report_services
id | min_serving_time | max_serving_time | report_site_id
1 | 00:00:30.094 | 00:15:30.662 | 1
2 | 00:00:07.566 | 00:07:49.72 | 2
3 | 00:00:07.787 | 00:26:27.587 | 3
我想按工作日从日期范围组中选择 MIN（min_serving_time）MAX（max_serving_time）
weekday | min | max
sunday | 00:00:05 | 00:08:55
monday | 00:01:51 | 00:05:21
tuesday | |
我可以像这样计算工作日的行数但是如何聚合值
select
count(extract(dow from report_sites.date) = 1 or null) as monday,
count(extract(dow from report_sites.date) = 2 or null) as tuesday,
count(extract(dow from report_sites.date) = 3 or null) as wednesday,
count(extract(dow from report_sites.date) = 4 or null) as thursday,
count(extract(dow from report_sites.date) = 5 or null) as friday
from report_sites
inner join "report_services"
on "report_sites"."id" = "report_services"."report_site_id"
where report_sites.date >='2016-11-02'
and
report_sites.date<='2016-11-07'
感谢您的任何帮助和建议。