C程序计算变化

Question

我正在尝试编写一个程序来计算变化，但它似乎并没有起作用。 我认为问题是欠1 /付1;当我试图在那里打印时，我什么都没得到（0）。 有什么帮助吗？

#include <stdio.h>

int main()
{
double owed, paid;
int  dollars, quarters, dimes, nickels, cents, remainder, owed1, paid1;
printf("how much did the customer have to pay ?\n");
scanf("%f",&owed); 
printf("how much did the customer pay ?\n");
scanf("%f",&paid); 
owed1 = owed * 100;  
paid1 = paid * 100;
int change = paid1 - owed1;
dollars =  change / 100;
remainder = change % 100;
quarters = remainder / 25;
remainder = remainder % 25;
dimes = remainder / 10;
remainder = remainder % 10;
nickels = remainder / 5;
remainder = remainder % 5;
cents = remainder;
printf("%d",dollars);
printf("Dollars:%d, Quarters:%d, Dimes:%d, Nickels:%d, Cents:%d", dollars , quarters , dimes , nickels , cents );
return 0;
}

Answer 1

您在scanf中使用%f，它是浮点数的格式说明符，但您的变量是双精度数。您应该使用%lf代替：

scanf("%lf",&owed); 

paid也是如此。您应该收到编译器的警告。