Question

我试图为学校编写这个代码，我绝对坚持我做错了，如果有人能指出我正确的方向，那将会有所帮助。尽力学习。我的程序没有计算出，在每月末，在扣除付款后，然后添加利息时，欠多少钱。它只显示相同的值。

#include<stdio.h>

int main()
{
float loan;
float interest;
int n;
float outstanding;
float outstanding2;
float princeable;
float payment;


printf("\nEnter the amount of the loan: \n ");
scanf("%f" , &loan);
printf("\nEnter monthly interest percentage\n ");
scanf("%f" , &interest);
printf("\nEnter monthly payments: \n ");
scanf("%f" , &payment);
printf("\nEnter number of monthly Payments: \n ");
scanf("%i" , &n);


while (n >= 0) {
    outstanding = (loan - payment);
    outstanding = (outstanding * (1 + (interest/100)));


    printf("\Outstanding Balance after %i =%.2f\n\n", n, outstanding);
    n--;
}

return 0;

}

Answer 1

在每次迭代中，您应该根据其先前的值计算outstanding，而不是根据初始贷款的价值计算，因为您还需要支付利息利息。

outstanding = loan;
while (n > 0) {
    outstanding = (outstanding - payment);
    outstanding = (outstanding * (1 + (interest/100)));

    printf("\Outstanding Balance after %i =%.2f\n\n", n, outstanding);
    n--;
}

Answer 2

这一行：

outstanding = (loan - payment);

循环中的

不正确，因为它每次都以初始loan值开头。它应该是：

outstanding = (outstanding - payment);

在进入循环之前，您还必须将outstanding设置为loan。

最重要的是，你有一个太多的循环迭代，以及\O字符串中的非法转义序列printf。

C程序计算简单利息支付

2 个答案: