Question

我对javascript很新，并试图列出失败密码中缺少的字符，告诉用户他们需要输入什么。

window.onload = function()
{
   var info = document.getElementById("info");

   var test = document.getElementById("myForm").test;

   test.onclick = function(e)
   {
     e.preventDefault();
     var pw = document.getElementById("myForm").pw.value;

     var formula = /(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9]).{6,}/;

     if(formula.test(pw))
     {
         document.getElementById("myForm").submit();
     }
     else if pw.match(/\d/g) == null {
        info.innerHTML = "You need a number";
        console.log(pw.match(/\d/g))

     } else {

       info.innerHTML = "You need a number."
     }

     };

};

以上只是第一次检查用户是否输入了带有现在号码的密码。但我一直在

Uncaught SyntaxError: Unexpected identifier

在chrome dev工具中，pw.match部分带下划线。我在网上看过其他地方，我的语法看起来很正确。我哪里错了？

Answer 1

你需要一些括号

$recordsTotal = User::whereHas('employee', function ($q) use ($company_id) {
     $q->where('company_id', $company_id);
})->count();

Answer 2

您需要围绕else if (pw.match(/\d/g) == null) { ...阻止条件的括号。

from turtle import Turtle, Screen
from random import choice, randrange

LENGTH = 200
LIMIT = 10
DELTA = 16

colors = ["blue", "orange", "cyan", "green", "purple", "black", "red", "magenta"]

def turtle_spiral(turtle, length, delta, limit):

    if length < limit:
        return

    extent = 360 / delta

    for radius in range(delta):
        turtle.circle(length - radius, extent=extent)
        if randrange(delta) == 0:
            turtle.color(choice(colors))

    turtle_spiral(turtle, length - delta, delta, limit)

yertle = Turtle(shape="turtle", visible=False)

yertle.speed("fastest")

yertle.penup()
yertle.sety(-LENGTH)
yertle.pendown()

yertle.showturtle()

turtle_spiral(yertle, LENGTH, DELTA, LIMIT)

screen = Screen()
screen.exitonclick()

Answer 3

根据： http://www.w3schools.com/js/js_if_else.asp 你错过了（和）if if。

在javascript

3 个答案: