Question

我正在尝试使用大型mongoDB自学mongoDb（每个文档总共大约1000万个文档）

我想尝试一些基础知识。例如，列出通过UsedCallories对所有用户进行排序的每个Activity。

db.getCollection('users').aggregate([
  {$group: {_id:"$Activities"}}, 
  {$sort: { UsedCallories: -1}}
],{allowDiskUse:true});

不幸的是，当我执行这个脚本时，它给了我：'脚本执行成功，但没有结果显示。'？

你能指点一下我错了吗？

缩短的示例文件：

{
  "Id": 1,
  "FirstName": "Casie",
  "LastName": "Crapo",
  "Email": "Casie.Crapo@databanken.db",
  "Weight": 92,
  "Length": 198,
  "Activities": [
    {
      "ActivityType": {
        "Name": "Sexual Activity",
        "CallPerSecond": 0.033333333
      },
      "StartCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "EndCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "StartDateTime": { $date: "2016-11-01T23:39:15Z" },
      "EndDateTime": { $date: "2016-11-02T02:38:45Z" },
      "UsedCallories": 772.63042705630426,
      "Measurements": [
        {
          "Heartrate": 142,
          "UnderPressure": 123,
          "Overressure": 156,
          "Speed": 0,
          "Coordinates": {
            "Lattidude": -10.81907,
            "Longitude": -16.16832
          }
        }
      ]
    }
  ]
}

更新'ExpectedOutput'：

因此，预期输出只是用户所有数组字段中所有活动的列表。在UsedCallories上排序。

"Activities": [
    {
      "ActivityType": {
        "Name": "Sexual Activity",
        "CallPerSecond": 0.033333333
      },
      "StartCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "EndCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "StartDateTime": { $date: "2016-11-01T23:39:15Z" },
      "EndDateTime": { $date: "2016-11-02T02:38:45Z" },
      "UsedCallories": 772.63042705630426,
      "Measurements": [
        ...
      ]
    },{
      "ActivityType": {
        "Name": "Sexual Activity",
        "CallPerSecond": 0.033333333
      },
      "StartCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "EndCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "StartDateTime": { $date: "2016-11-01T23:39:15Z" },
      "EndDateTime": { $date: "2016-11-02T02:38:45Z" },
      "UsedCallories": 52.63042705630426,
      "Measurements": [
        ...
      ]
    },{
      "ActivityType": {
        "Name": "Sexual Activity",
        "CallPerSecond": 0.033333333
      },
      "StartCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "EndCoordinates": {
        "Lattidude": -10.81907,
        "Longitude": -16.16832
      },
      "StartDateTime": { $date: "2016-11-01T23:39:15Z" },
      "EndDateTime": { $date: "2016-11-02T02:38:45Z" },
      "UsedCallories": 20.22442,
      "Measurements": [
        ...
      ]
    }
  ]

重复提问后更新

好的，感谢您对重复帖子的引用。但这不是同一个问题。

我设法使用其中的一部分来实际获得一些结果。查询更改为：

db.getCollection('users').aggregate([
    {$unwind: '$Activities'}, 
    {$sort: {'Activities.UsedCallories': -1}}, 
    {$group: {_id: '$_id', 'Activities': {$push: '$Activities'}}}
    ], {
  allowDiskUse:true
 })

现在返回GROUPED BY USER的所有活动，我更喜欢所有这些活动的LIST，而不是按用户分组

Answer 1

谢谢@chridam。添加我的评论作为答案。

db.getCollection('users').aggregate([{
    $unwind: "$Activities"
}, {
    $sort: {
        "Activities.UsedCallories": -1
    }
}, {
    $group: {
        _id: null,
        Activities: {
            $push: "$Activities"
        }
    }
}, {
    $project: {
        _id: 0,
        Activities: 1
    }
}], {
    allowDiskUse: true
});

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1 个答案: