Question

您好我有以下字符串：

Country number Time Status USA B30111 11:15 ARRIVED PARIS NC0120 14:40 ON TIME DUBAI RA007 14:45 ON TIME

我需要提取以下信息：

country = USA
number = B30111
time = 11:15
status = ARRIVED

country = PARIS
number = NC0120
time = 14:40
status = ON TIME

如何使用正则表达式从中提取上述数据？

Answer 1

你可以试试这个：

(?: (\w+) ([\w\d]+) (\d+\:\d+) (ARRIVED|ON TIME))

Explanation

由于状态可以包含多个单词，因此无法将其与出现的下一个国家区分开来，因此您必须将所有可能的状态添加为或在正则表达式

Java来源：

final String regex = "(?: (\\w+) ([\\w\\d]+) (\\d+\\:\\d+) (ARRIVED|ON TIME))";
final String string = "Country number Time Status USA B30111 11:15 ARRIVED PARIS NC0120 14:40 ON TIME DUBAI RA007 14:45 ON TIME\n\n\n";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
        System.out.println("country =" + matcher.group(1));
        System.out.println("number =" + matcher.group(2));
        System.out.println("time =" + matcher.group(3));
        System.out.println("status =" + matcher.group(4));
        System.out.println("");
}

<强>输出

country =USA
number =B30111
time =11:15
status =ARRIVED

country =PARIS
number =NC0120
time =14:40
status =ON TIME

country =DUBAI
number =RA007
time =14:45
status =ON TIME

Answer 2

如果您基于分割功能创建一个数组，那么您将拥有该数组中的每个单词。

String[] splitted = str.split(" ");

然后检查，试试这个： -

for(String test:splitted){
    System.out.println(test);
}

这看起来更像是一个CSV文件。

如何使用正则表达式从字符串值中提取数据？

2 个答案: