Am使用列表框项目中的复选框,如何从列表中获取所选复选框
<ListBox ItemsSource="{Binding NameList}" HorizontalAlignment="Left" Margin="16,68,0,12" Name="listBox1" Width="156" IsEnabled="True" SelectionMode="Multiple" Focusable="True" IsHitTestVisible="True" IsTextSearchEnabled="False" FontSize="12" Padding="5" SelectionChanged="listBox1_SelectionChanged">
<ListBox.ItemTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<CheckBox Content="{Binding Path=CNames}" />
</StackPanel>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
我尝试循环遍历listboxitems中的所选项目,但它在listboxitem中抛出异常
private void btnSelected(object sender, RoutedEventArgs e)
{
foreach (ListBoxItem item in listBox1.Items)
{
if (item.ToString() == "true")
{
MessageBox.Show(item.Content.ToString());
}
}
}
答案 0 :(得分:5)
您可以将每个项目的数据上下文移离UI,并创建一个ObservableCollection对象
public ObservableCollection<CheckedItem> List { get;set;}
public class CheckedItem : INotifyPropertyChanged
{
private bool selected;
private string description;
public bool Selected
{
get { return selected; }
set
{
selected = value;
OnPropertyChanged("Selected");
}
}
public string Description
{
get { return description; }
set
{
description = value;
OnPropertyChanged("Description");
}
}
/* INotifyPropertyChanged implementation */
}
然后在ListBox ItemTemplate
中<ItemTemplate>
<DataTemplate>
<CheckBox IsChecked="{Binding Path=Selected}"
Content={Binding Path=Description}" />
</DataTemplate>
</ItemTemplate>
您选择的项目现在可在ObservableCollection中使用,而不是循环使用UI元素
答案 1 :(得分:1)
让你的模板像这样
<ListBox.ItemTemplate>
<DataTemplate>
........
<CheckBox Content=""
IsChecked="{Binding IsSelected, Mode=TwoWay,
RelativeSource={RelativeSource FindAncestor,
AncestorType={x:Type ListViewItem}}}" />
..........
<!-- Use Other UIElements to Show your Data -->
然后上面的绑定将与您的模型isSelected和列表视图选择同步两种方式,然后在代码中使用SelectedItems。
For Each s As myPoco In myListView1.SelectedItems
' do something here with
Next
答案 2 :(得分:0)
我会建议这段代码:
private void save_Click(object sender, RoutedEventArgs e)
{
foreach (CheckBox item in list1.Items)
{
if (item.IsChecked)
{
MessageBox.Show(item.Content.ToString());
}
}
}