Question

假设我有以小时为单位的变量日期：分钟：第二种格式

var time1 = "12:34:19 PM"
var time2 = "12:29:25 PM"

我如何从时间1和时间2获得差异（持续时间）？以及我们如何将其更改为日期格式以进行差异处理？

Answer 1

您可以将新日期（）的时间转换为前一个日期和

之前的日期

使用getTime()获取时间戳并减去它们

var duration = new Date('datetime1').getTime() - new Date('datetime2').getTime()

因为时间戳是结果总数的1000倍，所以将它除以1000

var duration = durantion/1000;

我只是创建一个正确格式化秒数的函数，使其看起来像一个有效的持续时间

var time1 = "2016-11-02 12:34:19 PM"
var time2 = "2016-11-02 12:29:25 PM"

time1 = new Date(time1 ).getTime();
time2 = new Date(time2 ).getTime();
var duration = (time1 - time2) / 1000;

function formatTime(seconds) {
  var minutes = Math.floor(((seconds/3600)%1)*60);
  minutes = (minutes < 10) ? '0'+minutes : minutes;
  var seconds = Math.round(((seconds/60)%1)*60);
  seconds = (seconds < 10) ? '0'+seconds : seconds;
  return minutes+':'+seconds;
}

console.log('Duration: ' + formatTime(duration)+' secs')

Answer 2

这是工作脚本

String.prototype.toHHMMSS = function () {
    var sec_num = parseInt(this, 10); // don't forget the second param
    var hours   = Math.floor(sec_num / 3600);
    var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
    var seconds = sec_num - (hours * 3600) - (minutes * 60);

    if (hours   < 10) {hours   = "0"+hours;}
    if (minutes < 10) {minutes = "0"+minutes;}
    if (seconds < 10) {seconds = "0"+seconds;}
    return hours+':'+minutes+':'+seconds;
}
var timeStart = new Date("Mon Jan 01 2007 11:00:00 GMT+0530").getTime();
var timeEnd = new Date("Mon Jan 01 2007 11:32:51 GMT+0530").getTime();
var hourDiff = timeEnd - timeStart; //in ms
var secDiff = (hourDiff / 1000).toString(); //in s
alert(secDiff .toHHMMSS());

Answer 3

您可以使用如下构造函数创建Date个对象： Date(year, month, date, hours, minutes, seconds, ms)

在你的情况下你可以得到差异：

var date = new Date(2000, 1, 1, 12, 34, 19, 0, 0),
    date2 = new Date(2000, 1, 1, 12, 39, 25, 0, 0);

console.log(date2 - date); // in ms. You can do whatever you want with this value

您可以阅读有关Date对象here.

的更多信息

分钟持续时间差异javascript

3 个答案: