Question

我希望按周数进行去年的队列分析

输出结果为：

weeknumber session_count acq_count

37           5           3

43           2           2

...

到目前为止的MySql：

SELECT WEEK(datetime) AS weeknumber, COUNT(*) AS session_count, 
   acquisition as acq_count=(SELECT COUNT(*) FROM sessions WHERE acquisition=1 ) 
FROM sessions WHERE `datetime` >= NOW()- INTERVAL 365 DAY 
GROUP BY weeknumber

挑战：如何在同一个sql查询中获取匹配acquire = 1的行数？

感谢您的想法！佛瑞德

Answer 1

我想你想要这个查询

SELECT WEEK(datetime) AS weeknumber, COUNT(*) AS session_count, 
   SUM(acquisition=1) as acq_count 
FROM sessions WHERE `datetime` >= NOW()- INTERVAL 365 DAY 
GROUP BY weeknumber

按周数分组

1 个答案: