Question

我的第一个函数使用一个UUID数组并从表中返回一组行：

CREATE OR REPLACE FUNCTION fun1 (
  "UUID_" uuid []
)
RETURNS SETOF service AS
$body$
with recursive tree as (
 SELECT * FROM service 
  WHERE id = ANY($1) 
   UNION ALL
   SELECT service.* FROM service
      JOIN tree ON service.id = tree.parent_id)
 select distinct * from tree;
$body$
LANGUAGE 'sql'
VOLATILE
CALLED ON NULL INPUT
SECURITY INVOKER
COST 100 ROWS 1000;

现在我想写另一个将UUID列表作为varchar使用，并返回与第一个函数相同的数据。

我的不好尝试：

CREATE OR REPLACE FUNCTION fun2 (
  "UUID_" varchar
)
RETURNS TABLE (
  "ID" uuid,
  "NAME" varchar,
  "PARENT_ID" uuid
) AS
$body$
BEGIN
RETURN QUERY  
with recursive tree as (
 SELECT * FROM service 
  WHERE id = ANY(string_to_array($1, ',')::UUID[]) 
   UNION ALL
   SELECT service.* FROM service
      JOIN tree ON service.id = tree.parent_id)

     select distinct(ID), name, parent_id from tree;
END;
$body$
LANGUAGE 'plpgsql'
VOLATILE
CALLED ON NULL INPUT
SECURITY INVOKER
COST 100 ROWS 1000;

Answer 1

我会自己回答：

函数fun1可以在我使用它时使用varchar转换为UUID数组。所以我可以写：

select * from fun1('{some UUID array as varchar}'::UUID[]);

为什么Postgres没有返回结果？

1 个答案: