Question

我试图打印文本文件n次，但出于某种原因，它只循环一次，这是我的代码。

def makeStrings():
k = int(raw_input("Enter the number of bits in each binary string: "))
n = int(raw_input("Enter the number of binary strings to create: "))
name = raw_input("Enter the name of the file: ")
fileName = name
outputFile = open(fileName, "w")
int(k)
int(n)
for i in range(0,n):
    while(k>0):
        randomNumber= int(random.randint(0,1))
        outputFile.write(str(randomNumber))
        k = k - 1
    outputFile.write("\n")
outputFile.close()

如果你为k输入5，为n输入5，它应该写如下：

到文件，但它只写1行谁能给我一些见解？

Answer 1

while(k>0):

您永远不会将k重置为初始值。这个循环只发生一次

可能应该再次使用范围

for i in range(n):
    for j in range(k):
        # Don't subtract k...

或者，甚至将它全部缩小

with open(fileName, "w") as outputFile:
    for i in range(n):
        outputFile.write(''.join(str(random.randint(0,1)) for _ in range(k)))
        outputFile.write("\n")

打印N行K长二进制字符串

1 个答案: